A bird is flying an average altitude of 10 m above the ground after three seconds it settles on a branch that is 3 m above the ground, interpret the quotient to describe the rate of change in the first altitude give your answer to the nearest hundredth and remember that the bird is dissenting
The quotient in this scenario represents the rate of change in altitude of the bird while descending.
To calculate the rate of change, we need to find the difference in altitude and divide it by the time it takes for the bird to descend.
The initial altitude of the bird is 10 m above the ground, and after three seconds it settles on a branch that is 3 m above the ground. Therefore, the difference in altitude is 10 m - 3 m = 7 m.
The time it takes for the bird to descend is three seconds.
To calculate the rate of change, we divide the difference in altitude by the time:
Rate of change = Difference in altitude / Time
Rate of change = 7 m / 3 s
Rate of change ≈ 2.33 m/s (rounded to the nearest hundredth)
So, the quotient of 2.33 can be interpreted as the rate of change in the first altitude as the bird descends.
To interpret the quotient to describe the rate of change in the first altitude, we need to calculate the average rate of change (slope) between the initial altitude and the final altitude.
Initial altitude: 10 m above the ground
Final altitude: 3 m above the ground
Time elapsed: 3 seconds
To find the rate of change, we can use the formula:
Rate of change = Change in altitude / Change in time
Change in altitude = Final altitude - Initial altitude = 3 m - 10 m = -7 m
Change in time = 3 seconds
Rate of change = -7 m / 3 seconds
Dividing -7 by 3 gives us approximately -2.33.
Therefore, the quotient, rounded to the nearest hundredth, represents the rate of change in the first altitude as approximately -2.33 meters per second.