A bird is flying at an average altitude of 10 meters above the ground. After 3 seconds, it settles on a branch that is 3 meters above the ground. Interpret the quotient to describe the rate of change in the bird’s altitude. Give your answer to the nearest hundredth and remember that the bird is descending.(1 point)

The quotient that best represents the rate of change in the bird’s altitude is
meters/second.

nope

Bot?

its wrong

A whale is swimming at a current depth of 15 meters below the surface. It swims up toward the surface and arrives there 9.5 seconds later. Find the quotient that best describes the rate of change in the whale’s depth. Give your answer to the nearest hundredth.(1 point)

The quotient that best represents the rate of change in the whale’s depth is
meters/second.

To find the rate of change in the bird's altitude, we need to calculate the difference in altitude divided by the time it took.

The bird's initial altitude is 10 meters, and after 3 seconds, it settles on a branch 3 meters above the ground.

The difference in altitude is 10 meters - 3 meters = 7 meters.

The time it took is 3 seconds.

So, the rate of change in the bird's altitude is 7 meters / 3 seconds.

Dividing these values, we get:
7 / 3 ≈ 2.33

Therefore, the rate of change in the bird's altitude is approximately 2.33 meters per second, rounding to the nearest hundredth.

To calculate the rate of change in the bird's altitude, we need to find the difference in altitude and divide it by the time it took.

In this case, the bird started at an altitude of 10 meters and ended at an altitude of 3 meters. The difference in altitude is 10 - 3 = 7 meters.

The time it took for the bird to descend is 3 seconds.

Now we can calculate the rate of change in altitude:

Rate of change = Difference in altitude / Time

Rate of change = 7 meters / 3 seconds

Calculating this, we get a rate of change of approximately 2.33 meters per second.

Therefore, the quotient that best represents the rate of change in the bird's altitude is 2.33 meters/second.

The rate of change in the bird's altitude can be calculated by finding the difference in altitude and dividing it by the time taken.

Altitude difference: 10 meters - 3 meters = 7 meters
Time taken: 3 seconds

Rate of change = Altitude difference / Time taken
Rate of change = 7 meters / 3 seconds

To find the rate of change in meters per second, we divide the altitude difference by the time taken.

Rate of change = 2.33 meters/second