A pupil spent 1/6 of the pocket money on soda and 1/4 of the remainder on transport and was left with sh.36000. How much money did the pupil have at first?
Let's represent the amount of money the pupil had at first as "x".
The pupil spent 1/6 of the pocket money on soda, so the remaining amount of money is 5/6 * x.
The pupil then spent 1/4 of the remaining money on transport, leaving them with 3/4 * (5/6 * x) = 3/4 * 5/6 * x = 5/8 * x = sh.36000.
To find the value of "x", we can solve the equation:
5/8 * x = sh.36000.
To isolate "x", we can multiply both sides of the equation by 8/5:
(8/5) * (5/8 * x) = (8/5) * (sh.36000).
x = (8/5) * (sh.36000).
Simplifying:
x = (8 * 36000) / 5.
x = 288000 / 5.
x = sh.57600.
Therefore, the pupil had sh.57600 at first.
Let's assume that the pupil had x amount of money at first.
Step 1: The pupil spent 1/6 of the pocket money on soda.
The amount spent on soda is (1/6)x.
Step 2: The remainder after spending on soda is (5/6)x.
Step 3: The pupil spent 1/4 of the remainder on transport.
The amount spent on transport is (1/4)(5/6)x = (5/24)x.
Step 4: The amount left with the pupil is given as Sh.36000.
So, (5/6)x - (5/24)x = Sh.36000.
Simplifying the equation, we get
(20/24)x - (5/24)x = Sh.36000.
(15/24)x = Sh.36000.
Dividing both sides of the equation by (15/24), we get
x = (Sh.36000) * (24/15).
x = Sh.57600.
Therefore, the pupil had Sh.57600 at first.