A mountain goat is climbing to the top of a large cliff. The cliff is 50 feet higher than its starting point. If it takes the goat 22 minutes to climb this cliff, interpret the quotient to describe the rate of change in the goat’s elevation. Give your answer to the nearest hundredth.(1 point)
The quotient that best represents the rate of change in the goat’s elevation is __ feet/minute.
To find the quotient that represents the rate of change in the goat's elevation, we divide the change in elevation by the time taken.
The change in elevation is 50 feet, and the time taken is 22 minutes.
Therefore, the quotient is 50 feet / 22 minutes.
To find this value to the nearest hundredth, we divide 50 by 22.
50 / 22 = 2.27 (rounded to the nearest hundredth)
So the rate of change in the goat's elevation is approximately 2.27 feet/minute.
A bird is flying at an average altitude of 10 meters above the ground. After 3 seconds, it settles on a branch that is 3 meters above the ground. Interpret the quotient to describe the rate of change in the bird’s altitude. Give your answer to the nearest hundredth and remember that the bird is descending.(1 point)
The quotient that best represents the rate of change in the bird’s altitude is
meters/second.
To find the quotient that represents the rate of change in the bird's altitude, we divide the change in altitude by the time taken.
The change in altitude is 10 meters (initial altitude) - 3 meters (final altitude) = 7 meters (since the bird is descending).
The time taken is 3 seconds.
Therefore, the quotient is 7 meters / 3 seconds.
To find this value to the nearest hundredth, we divide 7 by 3.
7 / 3 = 2.33 (rounded to the nearest hundredth)
So the rate of change in the bird's altitude is approximately 2.33 meters/second.
A bird is flying at an average altitude of 10 meters above the ground. After 3 seconds, it settles on a branch that is 3 meters above the ground. Interpret the quotient to describe the rate of change in the bird’s altitude. Give your answer to the nearest hundredth and remember that the bird is descending.(1 point)
The quotient that best represents the rate of change in the bird’s altitude is __ meters/second.
To find the rate of change in the bird's altitude, we need to determine the difference in altitude (in meters) before and after the 3 seconds.
The initial altitude is 10 meters above the ground, and the final altitude is 3 meters above the ground (since the bird is descending).
Therefore, the change in altitude is 10 - 3 = 7 meters.
Since the bird settles on the branch after 3 seconds, the time taken is 3 seconds.
The rate of change in the bird's altitude can be calculated by dividing the change in altitude by the time taken.
Therefore, the quotient is 7 meters / 3 seconds.
To find this value to the nearest hundredth, we divide 7 by 3.
7 / 3 = 2.33
So, the rate of change in the bird's altitude is approximately 2.33 meters/second.
A whale is swimming at a current depth of 15 meters below the surface. It swims up toward the surface and arrives there 9.5 seconds later. Find the quotient that best describes the rate of change in the whale’s depth. Give your answer to the nearest hundredth.(1 point)
The quotient that best represents the rate of change in the whale’s depth is __ meters/second.
To find the rate of change in the whale's depth, we need to determine the difference in depth (in meters) before and after the 9.5 seconds.
The initial depth is 15 meters below the surface, and the final depth is at the surface (since the whale arrives there).
Therefore, the change in depth is 15 meters (negative value since the whale is swimming up).
Since it takes the whale 9.5 seconds to swim up, the time taken is 9.5 seconds.
The rate of change in the whale's depth can be calculated by dividing the change in depth by the time taken.
Therefore, the quotient is 15 meters / 9.5 seconds.
To find this value to the nearest hundredth, we divide 15 by 9.5.
15 / 9.5 = 1.58
So, the rate of change in the whale's depth is approximately 1.58 meters/second.
Solve using division of rational numbers. If a car’s value decreases by $2,500 in the first 6 months, how much does the value decrease per month? (Round to the nearest hundredth.) (1 point)
To find the amount the car's value decreases per month, we need to divide the decrease in value by the number of months.
The decrease in value is $2,500, and the number of months is 6.
Therefore, the quotient is $2,500 / 6.
To find this value to the nearest hundredth, we divide $2,500 by 6.
$2,500 / 6 ≈ $416.67
So, the value of the car decreases by approximately $416.67 per month.