Sara discarded 1/10 of the apples she picked as defective. Of the apples remaining, 300 were made into cider. The rest were sold as fresh fruit. What fraction of the total apples picked were sold as fresh fruit?
If $x$ represents the number of apples picked, then $x/10$ were discarded. This means there were $x - x/10 = (9/10)x$ apples that were not discarded. Of these, 300 were made into cider, leaving $((9/10)x - 300)$ to be sold as fresh fruit. The fraction of apples sold as fresh fruit is $(9/10)x - 300)/x = \boxed{\frac{9}{10}} - \frac{300}{x}$.
What is the answer?
The answer is $\boxed{\frac{9}{10}}$.
May you not explain how to get the answer
Apologies for the confusing explanation. The fraction of the total apples picked that were sold as fresh fruit is $\boxed{\frac{9}{10}}$.
Sara discarded 110 of the apples she picked as defective. Of the apples remaining, 300 were made into cider. The rest were sold as fresh fruit. What fraction of the total apples picked were sold as fresh fruit?
A. 3/10
B. Not enough information
C. 3/5
D. 4/5
The total number of apples picked is $110 + 300 + \text{apples sold as fresh fruit}$. Since the problem states that the remaining apples after discarding were made into cider and sold as fresh fruit, the total number of apples picked is equal to the sum of the apples made into cider and the apples sold as fresh fruit. Therefore, the fraction of the total apples picked that were sold as fresh fruit is $\boxed{\textbf{(D)}\ 4/5}$.
The town of Oak Manor measures 3.8 miles by 4.2 miles. Solve for the total area.(1 point)
Responses
15.96 mi
15.96 mi
16 mi2
16 mi squared
8 mi2
8 mi squared
15.96 mi2
The area of a rectangle is calculated by multiplying the length by the width. In this case, the area of Oak Manor is $3.8 \times 4.2 = 15.96$ square miles. Therefore, the total area is $\boxed{15.96 \text{ mi}^2}$.
A diver searches for a sunken treasure that is 97.2
feet below the surface. What is the diver's elevation when he is 23 of the way down? (1 point)
Responses
−48.5
ft.
negative 48 point 5 ft.
−64.8
ft.
negative 64 point 8 ft.
−32.4
ft.
negative 32 point 4 ft.
−145.8 ft.
To find the diver's elevation when he is 23% down, we can multiply 97.2 (the total depth) by 0.23 (23% as a decimal):
$97.2 \times 0.23 = 22.356$
Therefore, the diver's elevation is $\boxed{-22.356}$ feet.
A diver searches for a sunken treasure that is 97.2
feet below the surface. What is the diver's elevation when he is 23 of the way down? (1 point)
Responses
A. −48.5ft
B. −64.8ft
C. −32.4ft
D. −145.8 ft.
To find the diver's elevation when they are 23% of the way down, we can multiply 97.2 (the total depth) by 0.23 (23% as a decimal):
$97.2 \times 0.23 = 22.356$
Therefore, the diver's elevation is $\boxed{\textbf{(C)} \ -32.4\text{ ft}}$.
A diver searches for a sunken treasure that is 97.2
feet below the surface. What is the diver's elevation when he is 2/3 of the way down? (1 point)
Responses
A. −48.5ft
B. −64.8ft
C. −32.4ft
D. −145.8 ft.
To find the diver's elevation when they are 2/3 of the way down, we can multiply 97.2 (the total depth) by 2/3:
$97.2 \times \frac{2}{3} = 64.8$
Therefore, the diver's elevation is $\boxed{\textbf{(B)} \ -64.8\text{ ft}}$.
A basketball player is 6 2/3 feet tall. His infant son is 1/4 as tall. How tall is his son
To find the son's height, we can multiply the basketball player's height by 1/4:
$6 \frac{2}{3} \times \frac{1}{4} = \frac{20}{3} \times \frac{1}{4} = \frac{20}{12} = \frac{5}{3}$
Therefore, the son is $\boxed{\frac{5}{3}}$ feet tall.
A basketball player is 6 2/3 feet tall. His infant son is 1/4 as tall. How tall is his son
A.1 2/3
B.2 2/3
C. 1 1/2
D. 2 2/12
To find the son's height, we can multiply the basketball player's height by 1/4:
$6 \frac{2}{3} \times \frac{1}{4} = \frac{20}{3} \times \frac{1}{4} = \frac{5}{3}$
Therefore, the son is $\boxed{\textbf{(A)}\ 1 \frac{2}{3}}$ feet tall.