Calculate the time required for a 2,500 kg lifeboat to reach the water if released from a ship with 9.2-meter freeboard. The lifeboat is leveled with the freeboard. Assume free fall motion and use g = 9.8 m/s^2
To calculate the time required for the lifeboat to reach the water, we can use the formula for free fall motion:
h = 1/2 * g * t^2
Where:
h = vertical distance traveled (9.2 meters in this case)
g = acceleration due to gravity (9.8 m/s^2)
t = time
We can rearrange the equation to solve for t:
t = sqrt(2h/g)
Substituting the given values:
t = sqrt(2 * 9.2 / 9.8)
t = sqrt(1.8776)
t ≈ 1.37 seconds
Therefore, it will take approximately 1.37 seconds for the 2,500 kg lifeboat to reach the water if released from a ship with a 9.2-meter freeboard.
To calculate the time required for the lifeboat to reach the water, we can use the equation for free fall motion:
h = (1/2) * g * t^2
where:
h is the height (in meters) the lifeboat will fall
g is the acceleration due to gravity (9.8 m/s^2)
t is the time (in seconds) it takes for the lifeboat to fall
Since the lifeboat is leveled with the freeboard, the height it will fall is equal to the freeboard height. In this case, the freeboard height is 9.2 meters.
So, we can substitute these values into the equation:
9.2 = (1/2) * 9.8 * t^2
To solve for t, we can rearrange the equation:
t^2 = (2 * 9.2) / 9.8
t^2 = 18.4 / 9.8
t^2 ≈ 1.8776
Taking the square root of both sides:
t ≈ √1.8776
t ≈ 1.37 seconds
Therefore, the time required for the 2,500 kg lifeboat to reach the water, when released from a ship with a 9.2-meter freeboard, is approximately 1.37 seconds.