Use the given parts of a right spherical triangle ACB

C = 90°
B = 143° 44'
A = 60° 25'

Using the given parts of the right spherical triangle ACB, we can find the missing parts using the following formulas:

1. Law of Sines: sin(A)/sin(a) = sin(B)/sin(b) = sin(C)/sin(c)
2. Law of Cosines: cos(C) = cos(A) * cos(B) + sin(A) * sin(B) * cos(c)
3. Complementary Angle: A + C = 90°

1. Let's find angle A:
A + C = 90°
60° 25' + 90° = 150° 25'

2. Let's find angle B in degrees:
B = 143° 44'

3. Let's find angle B in minutes:
143° 44' = (143 * 60) + 44 = 8624 minutes

4. Let's find angle C:
C = 90°

Now we have all three angles of the right spherical triangle ACB:

A = 150° 25'
B = 143° 44'
C = 90°

To solve this right spherical triangle, we have the following given information:

C = 90°
B = 143° 44'
A = 60° 25'

Let's label the sides of the triangle as:

a = side opposite angle A
b = side opposite angle B
c = side opposite angle C (the hypotenuse)

In a right spherical triangle, the sum of the three angles is always 180 degrees. Since angle C is already given as 90 degrees, the sum of angles A and B must be 90 degrees as well.

Therefore, A + B = 90°

Substituting the values:

60° 25' + 143° 44' = 204° 9'

But since the sum of the angles of a triangle on a sphere cannot exceed 180°, we need to make adjustments.

Let's subtract 180° from the sum:

204° 9' - 180° = 24° 9'

Now, we have the adjusted sum of angles A and B. To use the law of sines, we need to convert the angles to radians:

Angle A = 24° 9' = 24 + 9/60 = 24.15 degrees = 0.4211 radians
Angle B = 143° 44' = 143 + 44/60 = 143.7333 degrees = 2.5061 radians

Now, let's apply the law of sines to find the lengths of the sides:

a/sin(A) = c/sin(C)
b/sin(B) = c/sin(C)

Since sin(90°) = 1, we can simplify the equations:

a = c/sin(A)
b = c/sin(B)

To find the values of a and b, we need to know the length of c, the hypotenuse. Without that information, we cannot determine the lengths of the sides a and b.

Please provide the length of the hypotenuse or any other relevant information so that I can proceed with solving the right spherical triangle.