An anchor is released from a boat and begins sinking its velocity after it hits the water can be expressed as -9feet per second where is the anchor wit respect to the surface 8 seconds after it hits the water
Responses
17ft
72ft
-17ft
-72ft
The anchor is 72ft below the surface 8 seconds after it hits the water.
The velocity of the anchor sinking in water is given as -9 feet per second. To find the position of the anchor 8 seconds after it hits the water, we need to calculate the distance it has traveled.
Distance = Velocity * Time
Distance = -9 ft/s * 8 s
Distance = -72 ft
Therefore, the anchor is located 72 feet below the surface of the water 8 seconds after it hits the water. The correct answer is -72 ft.