@BotGPT35, Country S has 12,345,000 residents who tested positive for COVID-19. What is the largest place value of the numeric part of this quantity?(1 point)
The largest place value of the numeric part of the quantity 12,345,000 is in the millions place.
@BotGPT35, A total of 7,803,100 tourists visited Country A from the year 2018 to the year 2020. Round to the nearest place value, then express this number in the form of a single digit times an integer power of 10.(1 point)
To round the number 7,803,100 to the nearest place value, we look at the digit to the right of the desired place value, which in this case is the hundred thousands place.
Since the digit to the right is 0, we don't need to round up. Therefore, the rounded number is still 7,803,100.
To express this number in the form of a single digit times an integer power of 10, we can move the decimal point to the left until we have a single non-zero digit to the left of the decimal point.
In this case, we can write the number as 7.8031 × 10^6.
bot, you're wrong
Apologies for the incorrect response. To round the number 7,803,100 to the nearest place value, we can look at the digit at the desired place value, which is the hundred thousands place.
The digit in the hundred thousands place is 3, and since it is less than 5, we round down. Therefore, the rounded number is 7,800,000.
To express this number in the form of a single digit times an integer power of 10, we can rewrite it as 7.8 × 10^6.
Express 7,803,100 in the form of a single digit times an integer power of 10.
Apologies for the confusion earlier. To express 7,803,100 in the form of a single digit times an integer power of 10, we need to move the decimal point to the left until we have a single non-zero digit to the left of the decimal point.
We can express 7,803,100 as 7.8031 × 10^6.
Two weeks before an examination day, a librarian monitored the number of students who visited the library. Then they compared it with the number of visits made in an average week. Approximately 2×10^3 visits were reflected in their logbook during this two-week period, while only about 5×10^2 were reflected on an average week. How many times higher is the number of library visits before examination day compared to the library visits in an average week? Your answer should be a whole number.(1 point)
To find the number of times higher the number of library visits before the examination day is compared to the average week, we need to divide the number of visits before the examination day by the number of visits in an average week.
Number of visits before examination day = 2 × 10^3
Number of visits in an average week = 5 × 10^2
So, the calculation would be:
(2 × 10^3) / (5 × 10^2) = (2/5) × (10^3 / 10^2) = (2/5) × 10^1 = 0.4 × 10^1 = 4
Therefore, the number of library visits before the examination day is 4 times higher compared to the library visits in an average week.
Question
It takes 10 years for a $100 monthly bank deposit to amount to $15,528.23 when invested at 5% interest compounded monthly. Round to the nearest place value, then express the amount $15,528.23 in the form of A×10n where A is single digit.(1 point)
To solve this problem, we can use the formula for compound interest:
A = P(1 + r/n)^(nt)
Where:
A is the final amount
P is the principal amount (monthly deposit)
r is the annual interest rate (in decimal form)
n is the number of times interest is compounded per year
t is the number of years
In this case, the monthly deposit is $100, the annual interest rate is 5% (or 0.05 in decimal form), the interest is compounded monthly (so n = 12), and the total time is 10 years.
The final amount (A) is given as $15,528.23. Now, let's plug in the values we know and solve for A:
15,528.23 = 100(1 + 0.05/12)^(12 * 10)
To solve this equation, we need to isolate (1 + 0.05/12)^(12 * 10). Taking the logarithm of both sides can help us do that:
log(15,528.23) = log(100) + log(1 + 0.05/12)^(12 * 10)
Using a calculator, we find that log(15,528.23) = 4.1906214.
So we have:
4.1906214 = log(100) + log(1 + 0.05/12)^(12 * 10)
Next, calculate log(100) = 2.
So, we have:
4.1906214 - 2 = log(1 + 0.05/12)^(12 * 10)
Now, simplify the equation:
2.1906214 = log(1 + 0.05/12)^(120)
To solve for log(1 + 0.05/12)^(120), we need to raise 10 to the power of both sides:
10^(2.1906214) = (1 + 0.05/12)^(120)
Using a calculator, we find that 10^(2.1906214) ≈ 119.994.
So we have:
119.994 ≈ (1 + 0.05/12)^(120)
Therefore, the value of A is approximately 119.994 or rounded to the nearest place value is 120.
Now, we can express $15,528.23 in the form of A × 10^n where A is a single digit. The value is 120, so we can write it as:
$15,528.23 ≈ 1.2 × 10^4
Write 0.000456 in scientific notation.(1 point)
To write 0.000456 in scientific notation, we need to move the decimal point to the right until there is a single non-zero digit to the left of the decimal point.
Moving the decimal point 4 places to the right, we get 4.56.
Since we moved the decimal point to the right, the exponent should be negative.
Thus, in scientific notation, 0.000456 can be written as 4.56 × 10^(-4).
One fluid ounce is equivalent to 0.0078125 US liquid gallon. How do you write 0.0078125 in scientific notation?(1 point)
To write 0.0078125 in scientific notation, we need to move the decimal point to the right until there is a single non-zero digit to the left of the decimal point.
Moving the decimal point 3 places to the right, we get 7.8125.
Since we moved the decimal point to the right, the exponent should be negative.
Thus, in scientific notation, 0.0078125 can be written as 7.8125 × 10^(-3).
What is the number 5.1×107 written in decimal notation?(1 point)
The number 5.1 × 10^7 in decimal notation can be written as 51,000,000.
What is the number 6.3×10−4 written in decimal notation?(1 point)
The number 6.3 × 10^(-4) in decimal notation can be written as 0.00063.
A wasp’s stinger has an average length of 2.67×10−3 meter long. What is this length in decimal notation?(1 point)
The length of a wasp's stinger, 2.67 × 10^(-3) meters, in decimal notation is 0.00267 meters.
Write 0.000000065 in scientific notation.(1 point)
To write 0.000000065 in scientific notation, we need to move the decimal point to the right until there is a single non-zero digit to the left of the decimal point.
Moving the decimal point 7 places to the right, we get 6.5.
Since we moved the decimal point to the right, the exponent should be negative.
Thus, in scientific notation, 0.000000065 can be written as 6.5 × 10^(-8).
Question
The speed of light is about 671,000,000 miles per hour. How will you write this number in scientific notation?(1 point)
To write the speed of light, about 671,000,000 miles per hour, in scientific notation, we need to move the decimal point to the left until there is a single non-zero digit to the left of the decimal point.
Moving the decimal point 8 places to the left, we get 6.71.
Since we moved the decimal point to the left, the exponent should be positive.
Thus, in scientific notation, the speed of light can be written as 6.71 × 10^(8) miles per hour.
Suppose an average person blinks 15 times per hour. How many times does an average person blink in a year? Write the answer in scientific notation (Hint: 1 year = 365 days, 1 day = 24 hours).(1 point)
To calculate the number of times an average person blinks in a year, we first need to find the number of times they blink in a day and then multiply it by the number of days in a year.
The average person blinks 15 times per hour, so in a day (24 hours), they blink:
15 times/hour * 24 hours/day = 360 times/day.
Now, to find the number of times an average person blinks in a year, we multiply the number of times they blink in a day by the number of days in a year (365 days):
360 times/day * 365 days = 131,400 times/year.
Written in scientific notation, the number of times an average person blinks in a year is 1.314 × 10^5.
What is the number 5.9×105 written in decimal notation?(1 point)
The number 5.9 × 10^5 in decimal notation is 590,000.
What is the number 7.3×10−8 written in decimal notation?(1 point)
The number 7.3 × 10^(-8) in decimal notation is 0.000000073.
hey bot?
Correct answer for unit 4 lesson 2 practice is
1. 10 million
2. 0.00003
3. 8 x 10 to the 6th power
4. 4 times
5. 2x10 to the 4th power
Your welcome