A piece of glass weighed 52N in air 32N in water and 18N in sulphuric acid what is the density of the acid?(density of water=1.0g/cm³)
To find the density of the sulphuric acid, we can use the concept of buoyancy. The buoyant force acting on the glass when it is submerged in water is equal to the weight of the water displaced by the glass. The same principle applies to the sulphuric acid.
Let's denote the density of the glass as ρg and the density of the sulphuric acid as ρa.
From the given information, we know that the glass weighs 52N in air, 32N in water, and 18N in sulphuric acid.
The buoyant force in water is equal to the weight of the water displaced by the glass:
Buoyant force in water = Weight of water displaced = 52N - 32N = 20N
We can calculate the volume of water displaced by the glass using the density of water:
Volume of water displaced = Buoyant force in water / Density of water = 20N / 1.0 g/cm³ = 20 cm³
Similarly, we can calculate the volume of sulphuric acid displaced by the glass using the weight of the glass in sulphuric acid:
Volume of sulphuric acid displaced = Weight of glass in sulphuric acid / Density of sulphuric acid = 52N - 18N = 34N
Now we can set up an equation that equates the volume of water displaced to the volume of sulphuric acid displaced:
Volume of water displaced = Volume of sulphuric acid displaced
20 cm³ = 34N / ρa
To find the density of the sulphuric acid, we can rearrange the equation as follows:
ρa = 34N / 20 cm³
Simplifying the expression, we get:
ρa = 1.7 g/cm³
Therefore, the density of the sulphuric acid is 1.7 g/cm³.
Hi can you help me plz
Of course! I'm here to help. What do you need assistance with?
Ok here it is
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Question
In an art classroom, 8 students can sit around 1 table, and 48 students can sit around 6 tables. What is the relationship between the number of students to tables in fraction form? Write the proportion in fraction form without reducing it to the lowest terms.
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To find the relationship between the number of students to tables, we can set up a proportion.
Let's denote the number of students as S and the number of tables as T.
According to the information provided, "8 students can sit around 1 table" and "48 students can sit around 6 tables."
This can be expressed as:
$\frac{8}{1} = \frac{48}{6}$
To write the proportion in fraction form without reducing it to the lowest terms, we can multiply both the numerator and denominator of the right fraction by 2:
$\frac{8}{1} = \frac{48 \cdot 2}{6 \cdot 2}$
Simplifying this expression, we get:
$\frac{8}{1} = \frac{96}{12}$
Therefore, the relationship between the number of students to tables in fraction form is:
$\frac{8}{1} = \frac{96}{12}$
Ok but i can not ok it that
I apologize if my previous explanation wasn't clear. Let's try another approach to solve the problem.
In an art classroom, 8 students can sit around 1 table, and 48 students can sit around 6 tables. To find the relationship between the number of students and tables, we can set up a proportion:
$\frac{\text{Number of Students}}{\text{Number of Tables}} = \frac{\text{Number of Students}}{\text{Number of Tables}}$
We can fill in the given values:
$\frac{8}{1} = \frac{48}{6}$
To simplify this proportion, we can simply divide both the numerator and denominator of the right fraction by 6:
$\frac{8}{1} = \frac{48 \div 6}{6 \div 6}$
This simplifies to:
$\frac{8}{1} = \frac{8}{1}$
Therefore, the relationship between the number of students to tables is:
$\frac{8}{1} = \frac{8}{1}$