A group of friends wants to go to the amusement park. They have no more than $155 to spend on parking and admission. Parking is $18, and tickets cost $24 per person, including tax. What is the maximum number of people who can go to the amusement park?
Let n be the number of friends. The total cost for n friends to enter is 24n, and the total cost for parking and admissions is 18 + 24n.
We want to find the maximum number of friends, such that 18 + 24n ≤ 155.
Subtracting 18 from both sides, we get: 24n ≤ 137.
Dividing both sides by 24, we get: n ≤ 5.7.
The maximum number of friends who can go to the amusement park is 5 because you can't have a fraction of a person. Answer: \boxed{5}.
To find the maximum number of people who can go to the amusement park, we need to calculate how much money will be left after accounting for parking and admission costs.
The cost of parking is $18. So, we subtract this from the total budget:
$155 - $18 = $137
Now, we need to find out how much each person's ticket costs, including tax. The ticket price is $24.
To calculate the number of people who can go to the amusement park, we divide the remaining budget by the cost of each ticket:
$137 ÷ $24 = 5.71
Since we cannot have a fraction of a person, we need to round down the number of people who can go to the amusement park:
5 people can go to the amusement park, with $5 left over.
Therefore, the maximum number of people who can go to the amusement park is 5.
these are the answers I have A group of friends wants to go to the amusement park. They have no more than $560 to spend on parking and admission. Parking is $19.25, and tickets cost $19.75 per person, including tax. Which inequality can be used to determine xx, the maximum number of people who can go to the amusement park?
Answer
Multiple Choice Answers
560, is less than or equal to, 19, point, 7, 5, x, plus, 19, point, 2, 5560≤19.75x+19.25
560, is less than or equal to, 19, point, 7, 5, left bracket, x, plus, 19, point, 2, 5, right bracket560≤19.75(x+19.25)
560, is greater than or equal to, 19, point, 7, 5, left bracket, x, plus, 19, point, 2, 5, right bracket560≥19.75(x+19.25)
560, is greater than or equal to, 19, point, 7, 5, x, plus, 19, point, 2, 5560≥19.75x+19.25
these are the answers that i have 560, is less than or equal to, 19, point, 7, 5, x, plus, 19, point, 2, 5560≤19.75x+19.25
560, is less than or equal to, 19, point, 7, 5, left bracket, x, plus, 19, point, 2, 5, right bracket560≤19.75(x+19.25)
560, is greater than or equal to, 19, point, 7, 5, left bracket, x, plus, 19, point, 2, 5, right bracket560≥19.75(x+19.25)
560, is greater than or equal to, 19, point, 7, 5, x, plus, 19, point, 2, 5560≥19.75x+19.25
Select the values that make the inequality start fraction, p, divided by, minus, 4, end fraction, ≤, 2
−4
p
≤2 true. Then write an equivalent inequality, in terms of pp.
(Numbers written in order from least to greatest going across.)
I NEED HELP
To find the maximum number of people who can go to the amusement park, we need to calculate the total cost of parking and tickets for the group and see how many times the total cost fits into the available budget.
Let's start by calculating the total cost for parking and tickets:
Total cost = cost of parking + (cost of ticket * number of people)
The cost of parking is given as $18.
The cost of the ticket per person is given as $24.
Using these values, we can substitute them into the formula:
Total cost = $18 + ($24 * number of people)
Next, we need to set up an equation to represent the given budget constraint:
Total cost ≤ available budget
Substituting the previous formula into the inequality, we get:
$18 + ($24 * number of people) ≤ $155
Now, let's solve for the maximum number of people who can go to the amusement park:
$24 * number of people ≤ $155 - $18
$24 * number of people ≤ $137
Dividing both sides of the inequality by 24, we have:
number of people ≤ $137 / $24
number of people ≤ 5.7083 (rounded to 4 decimal places)
Since we are dealing with a whole number of people, the maximum number of people who can go to the amusement park is 5.
Therefore, the group of friends can have a maximum of 5 people to stay within their budget of $155.