Sarina tracks her time spent on homework each night for a week, in minutes. She collects the following times: 51, 60, 25, 15, 20, 5, 35. When she solves for the mean absolute deviation, what number will she use for the divisor?(1 point)
Responses
30.1
30.1
55
55
7
7
15.9
To find the mean absolute deviation, Sarina first needs to find the mean (average) of her time spent on homework.
Mean = (51 + 60 + 25 + 15 + 20 + 5 + 35) / 7 = 27.43 (rounded to two decimal places)
Next, she needs to find the average distance of each data point from the mean.
Mean absolute deviation = [(51-27.43) + (60-27.43) + (25-27.43) + (15-27.43) + (20-27.43) + (5-27.43) + (35-27.43)] / 7
Simplifying this expression, we get:
Mean absolute deviation = (23.57 + 32.57 + -2.43 + -12.43 + -7.43 + -22.43 + 7.57) / 7
Mean absolute deviation = -0.93
Therefore, Sarina would use 7 as the divisor when calculating the mean absolute deviation. So, the correct answer is 7.
To find the mean absolute deviation, Sarina first needs to calculate the mean of her time spent on homework. The mean is obtained by summing up all the values and then dividing by the number of values. In this case, there are 7 values.
Sum of times spent on homework = 51 + 60 + 25 + 15 + 20 + 5 + 35 = 211
Mean = Sum/Number of values = 211/7 = 30.1
Therefore, Sarina will use the number 30.1 as the divisor to calculate the mean absolute deviation. The correct answer is 30.1.