Mean Absolute Deviation Practice
Complete this assessment to review what you've learned. It will not count toward your grade.
3 of 53 of 5 Items
Question
Use the table to answer the question.
Data Point Absolute Deviation
5 17.3
10 12.3
45
12 10.3
27
35 12.7
The table lists Jude’s data for how many people walk into a store each half hour. The mean is 22.3. Identify the absolute deviation for each missing value. Round each value to the nearest tenth.
(1 point)
Data Point Absolute Deviation
5 17.3
10 12.3
45
12 10.3
27
35 12.7
To find the absolute deviation for each missing value, we need to subtract the mean (22.3) from the missing values and take the absolute value.
For the missing value after 45, we have:
Absolute Deviation = |45 - 22.3| = 22.7
For the missing value after 27, we have:
Absolute Deviation = |27 - 22.3| = 4.7
Therefore, the updated table is:
Data Point | Absolute Deviation
5 17.3
10 12.3
45 22.7
12 10.3
27 4.7
35 12.7
To find the absolute deviation for each missing value, we need to calculate the difference between each data point and the mean, and then take the absolute value of that difference.
First, let's find the absolute deviation for the missing value after 45.
Step 1: Subtract the mean (22.3) from the data point (45):
45 - 22.3 = 22.7
Step 2: Take the absolute value of the difference:
|22.7| = 22.7
So, the absolute deviation for the missing value after 45 is 22.7.
Next, let's find the absolute deviation for the missing value after 27.
Step 1: Subtract the mean (22.3) from the data point (27):
27 - 22.3 = 4.7
Step 2: Take the absolute value of the difference:
|4.7| = 4.7
So, the absolute deviation for the missing value after 27 is 4.7.
Now, let's summarize the absolute deviations:
Data Point Absolute Deviation
5 17.3
10 12.3
45 22.7
12 10.3
27 4.7
35 12.7