Starting from 130 feet away, a person on bicycle rides towards a checkpoint and then passes it. The rider is traveling at a constant rate of 25 feet per second. The distance between the bicycle and the checkpoint is given by the equationd equals absolute value of the quantity 130 minus 25 t. At what times is the bike 15 feet away from the checkpoint?
(1 point)
Responses
4.6 sec and 9.2 sec
4.6 sec and 9.2 sec
2.9 sec and 5.8 sec
2.9 sec and 5.8 sec
4.6 sec and 5.8 sec
4.6 sec and 5.8 sec
2.9 sec and 3.3 sec
To find the times when the bike is 15 feet away from the checkpoint, we need to solve the equation:
|130 - 25t| = 15
Since we are taking the absolute value, we can have two cases:
Case 1: 130 - 25t = 15
Solving this equation, we get: t = 4.6 seconds
Case 2: 130 - 25t = -15
Solving this equation, we get: t = 5.8 seconds
Therefore, the correct answer is: 4.6 seconds and 5.8 seconds.
suppose R={1,3,5,7,9,11,13,15,17} and D={3,6,9,12,15,18,21,24,27}, what is R◠D?
To find the times when the bike is 15 feet away from the checkpoint, we need to solve the equation:
|130 - 25t| = 15
First, let's consider the positive value of the absolute function:
130 - 25t = 15
Solve for t:
-25t = 15 - 130
-25t = -115
t = -115 / -25
t = 4.6
Next, let's consider the negative value of the absolute function:
130 - 25t = -15
Solve for t:
-25t = -15 - 130
-25t = -145
t = -145 / -25
t = 5.8
Now we have found the times when the bike is 15 feet away from the checkpoint:
t = 4.6 sec and t = 5.8 sec
Therefore, the correct answer is:
4.6 sec and 5.8 sec
To find the times when the bike is 15 feet away from the checkpoint, we need to solve the equation:
d = |130 - 25t| = 15
To remove the absolute value, we can consider two cases:
Case 1: 130 - 25t = 15
Solving this equation, we get:
130 - 15 = 25t
115 = 25t
t = 4.6 seconds
Case 2: 130 - 25t = -15
Solving this equation, we get:
130 + 15 = 25t
145 = 25t
t = 5.8 seconds
Therefore, the bike is 15 feet away from the checkpoint at t = 4.6 seconds and t = 5.8 seconds.
The correct response is:
4.6 sec and 5.8 sec