An ant is climbing vertically on a stick. Its motion is shown on the following graph of vertical position y vs. time t.
What is the average speed of the ant between the times t = 0s and t = 10 s
To find the average speed of the ant between t = 0s and t = 10s, we need to calculate the total distance traveled by the ant and divide it by the total time taken.
Looking at the graph, we can see that the ant starts at a position of y = 0cm and reaches a maximum height of y = 8cm at t = 5s. The ant then descends back to y = 0cm at t = 10s.
The total distance traveled by the ant is twice the vertical distance from y = 0cm to y = 8cm. So, the total distance traveled is 2 * 8cm = 16cm.
The total time taken is 10s - 0s = 10s.
Average speed = Total distance traveled / Total time taken
= 16cm / 10s
= 1.6 cm/s
Therefore, the average speed of the ant between t = 0s and t = 10s is 1.6 cm/s.
To calculate the average speed of the ant between the times t = 0s and t = 10s, we need to find the total distance covered by the ant within that time interval and divide it by the total time taken.
Looking at the graph, let's determine the distance traveled by the ant at t = 0s and t = 10s.
At t = 0s, the ant's vertical position is y = 0.
At t = 10s, the ant's vertical position is y = 15 cm.
Therefore, the distance covered by the ant between t = 0s and t = 10s is:
Distance = y(final) - y(initial)
= 15 cm - 0 cm
= 15 cm.
Next, we divide the distance covered by the total time taken:
Average Speed = Distance / Time
= 15 cm / 10 s
= 1.5 cm/s.
Hence, the average speed of the ant between the times t = 0s and t = 10s is 1.5 cm/s.