Solve the equation.
Three-eighths times p equals 9.
(1 point)
Responses
p equals 72.
Image with alt text: p equals 72.
p equals 36.
Image with alt text: p equals 36.
p equals 48.
Image with alt text: p equals 48.
p equals 24.
Image with alt text: p equals 24.
To solve the equation:
Three-eighths times p equals 9.
We can set up the equation:
(3/8)p = 9
To isolate p, we can multiply both sides of the equation by the reciprocal of 3/8, which is 8/3:
[(3/8)p] x (8/3) = 9 x (8/3)
The 3 in the numerator and denominator cancel out on the left side and the equation becomes:
p = (9 x 8) / 3
Simplifying the right side gives:
p = 72 / 3
p = 24
Therefore, the solution to the equation is p = 24.
wrong
I apologize for the mistake. Let's solve the equation correctly.
To solve the equation "Three-eighths times p equals 9," we can set up the equation as:
(3/8)p = 9
To isolate p, we can multiply both sides of the equation by the reciprocal of 3/8, which is 8/3:
(3/8)p * (8/3) = 9 * (8/3)
On the left side, the 3 in the numerator cancels out with the 3 in the denominator:
p = 9 * (8/3)
Simplifying the right side gives:
p = 24
Therefore, the solution to the equation is p = 24.
You have a rack that can hold 30 CDs. You can fit 7 more CDs on the rack before the rack is full. Which equation models this situation appropriately, where x represents the number of CDs?
(1 point)
Responses
x plus 30 equals 7.
Image with alt text: x plus 30 equals 7.
x minus 7 equals 30.
Image with alt text: x minus 7 equals 30.
7 plus 30 equals x.
Image with alt text: 7 plus 30 equals x.
x plus 7 equals 30
The appropriate equation that models the situation is:
x plus 7 equals 30.
This equation represents that the number of CDs, x, added to the 7 CDs that can fit on the rack before it is full will be equal to the total capacity of the rack, which is 30 CDs.
You have a rack that can hold 30 CDs. You can fit 7 more CDs on the rack before the rack is full. How many CDs are in the rack?
(1 point)
Responses
13
13
23
23
7
7
37
37
To find out how many CDs are in the rack, we need to calculate the number of CDs that can fit before the rack is full and then add it to the rack's total capacity.
We are given that we can fit 7 more CDs on the rack before it is full. This means that the current number of CDs on the rack is 30 - 7 = 23.
Therefore, there are 23 CDs in the rack.
Solve the equation.
23 equals 7 times x.
(1 point)
Responses
x equals twenty-three sevenths.
Image with alt text: x equals twenty-three sevenths.
x equals seven twenty-thirds.
Image with alt text: x equals seven twenty-thirds.
x equals 3 and one-seventh.
Image with alt text: x equals 3 and one-seventh.
x equals 3.
To solve the equation "23 equals 7 times x," we can divide both sides of the equation by 7:
23/7 = (7x)/7
Simplifying the right side gives:
23/7 = x
Therefore, the solution to the equation is x equals 23/7 or 3 and one-seventh.
The correct response is:
x equals 3 and one-seventh.
Image with alt text: x equals 3 and one-seventh.
Solve the equation.
b plus 8 equals 12.2.
(1 point)
Responses
b equals 4.
Image with alt text: b equals 4.
b equals 4.2.
Image with alt text: b equals 4.2.
b equals 5.7.
Image with alt text: b equals 5.7.
b equals 5.2.