3(2i−7)=6i−21
infinite solutions
i = 5\
i = 4/13
i = -1/3
i = 8
There are no real solutions to the equation 3(2i−7)=6i−21. However, there are infinite solutions in the form of complex numbers.
To solve the equation 3(2i - 7) = 6i - 21, we can start by distributing the 3 on the left side:
6i - 21 = 6i - 21.
The equation simplifies to:
0 = 0.
Since this equation is always true, it means that any value of i will satisfy the equation. Therefore, this equation has an infinite number of solutions, and any value of i can be a solution.