A six-sided die with sides labeled 1 through 6 will be rolled once. Each number is equally likely to be rolled.
What is the probability of rolling a number greater than 2 ?
Write your answer as a fraction in simplest form.
There are three numbers greater than 2 on the six-sided die: 3, 4, and 5.
Since each number is equally likely to be rolled, the probability of rolling a number greater than 2 is $\frac{3}{6} = \boxed{\frac{1}{2}}$.
To find the probability of rolling a number greater than 2 on a six-sided die, we need to determine how many of the six sides satisfy this condition.
Step 1: Determine the favorable outcomes.
The numbers greater than 2 on a six-sided die are 3, 4, 5, and 6. So, there are four favorable outcomes.
Step 2: Determine the total possible outcomes.
Since the die has six sides labeled 1 through 6, there are six possible outcomes.
Step 3: Calculate the probability.
The probability is equal to the number of favorable outcomes divided by the number of total possible outcomes.
Probability = Favorable outcomes / Total possible outcomes
Probability = 4 / 6
Now, let's simplify the fraction.
Probability = 2 / 3
Therefore, the probability of rolling a number greater than 2 on a six-sided die is 2/3.