jeffery made a scale drawing of a house and it lot. he used the scale 7 inches : 4 feet. if the actual width of the backyard is 48 feet ,how wide is the yard in drawing?
To find the width of the yard in the drawing, we need to use the given scale of 7 inches : 4 feet. We can set up a proportion to solve for the width of the yard in the drawing:
7 inches / 4 feet = x inches / 48 feet
Cross multiplying gives us:
7 inches * 48 feet = x inches * 4 feet
336 inches = 4x
Dividing both sides by 4:
84 inches = x
Therefore, the width of the yard in the drawing is 84 inches.
To find the width of the yard in the drawing, we can use the scale given.
According to the scale, 7 inches in the drawing represents 4 feet in reality.
First, we need to convert the actual width of the backyard (48 feet) to inches, as we want the answer in terms of inches.
Since 1 foot is equal to 12 inches, the actual width of the backyard in inches would be 48 feet * 12 inches/foot = 576 inches.
Next, we can set up a proportion to solve for the width of the yard in the drawing:
7 inches / 4 feet = x inches / 576 inches
Cross-multiplying, we get:
4 feet * x inches = 7 inches * 576 inches
Simplifying, we have:
4x = 7 * 576
Dividing both sides by 4, we obtain:
x = (7 * 576) / 4
Evaluating the expression on the right:
x = 7 * 144
x = 1008 inches
Therefore, the width of the yard in the drawing is 1008 inches.