Solve for b in the following equation: A=12(a+b)
A. b=12A−a
B. b=12A+a
C. b=2A−a
D. b=2A+a
To solve for b, we can isolate it on one side of the equation.
Starting with the given equation:
A = 12(a+b)
Distribute the 12 to both terms inside the parentheses:
A = 12a + 12b
Subtract 12a from both sides of the equation to isolate the term containing b:
A - 12a = 12b
Now divide both sides of the equation by 12:
(A - 12a)/12 = b
Simplifying the left side:
A/12 - 12a/12 = b
A/12 - a = b
Thus, the solution is:
B. b = A/12 - a
To solve for b in the equation A = 12(a+b), we can follow these steps:
1. Distribute the 12 to both terms inside the parentheses:
A = 12a + 12b
2. Rearrange the equation to isolate the term with b:
A - 12a = 12b
3. Divide both sides of the equation by 12 to solve for b:
(b = A - 12a) / 12
Therefore, the correct answer is A. b = 12A - a.