The temperature at the end of the day was 64 degrees. The temperature had increased twice during the day, once by 8 degrees and another time by 4 degrees.
Which expression shows what the temperature was at the start of the day?
(1 point)
Responses
64 – 8 – 4
64 – 8 – 4
64 + 8 – 4
64 + 8 – 4
64 – 8 + 4
64 – 8 + 4
78 + 5 + 7
show your work
To determine the temperature at the start of the day, we need to subtract the total increase in temperature from the final temperature of 64 degrees.
The first increase was by 8 degrees, so we subtract 8: 64 - 8 = 56 degrees.
The second increase was by 4 degrees, so we subtract another 4: 56 - 4 = 52 degrees.
Therefore, the expression that shows what the temperature was at the start of the day is 64 - 8 - 4.
To find the temperature at the start of the day, we need to subtract the two increases in temperature from the final temperature of 64 degrees.
First, let's subtract the first increase of 8 degrees:
64 - 8 = 56
Next, let's subtract the second increase of 4 degrees from the result above:
56 - 4 = 52
Therefore, the expression that shows what the temperature was at the start of the day is:
64 - 8 - 4