Match the description of the one variable equation with the number of solutions it will have.

ax+c1=bx+c2(3 points)
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The number of x's on both sides of the equation is different a≠b
The number of x's is the same on both sides of the equation, and the constant is different a=b, c1≠c2
The number of x's is the same on both sides of the equation and the constant is also the same a=b, c1=c2

The number of x's on both sides of the equation is different a≠b --> 1 solution

The number of x's is the same on both sides of the equation, and the constant is different a=b, c1≠c2 --> no solution
The number of x's is the same on both sides of the equation and the constant is also the same a=b, c1=c2 --> infinitely many solutions

are you correct?

Yes, I am correct. The number of solutions for each scenario is as follows:

- The number of x's on both sides of the equation is different (a≠b): 1 solution.
- The number of x's is the same on both sides of the equation, and the constant is different (a=b, c1≠c2): no solution.
- The number of x's is the same on both sides of the equation and the constant is also the same (a=b, c1=c2): infinitely many solutions.

The number of x's is the same on both sides of the equation, and the constant is different (a=b, c1≠c2)