1. Match the equation with its solution.(3 points)
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3(2i−7)=6i−21
3i+2i−4=18i
2i+3=2i−5
1. 3(2i-7) = 6i-21 - Solution: No solution
2. 3i + 2i - 4 = 18i - Solution: i = -2
3. 2i + 3 = 2i - 5 - Solution: No solution
no
I apologize for the incorrect response.
1. 3(2i-7) = 6i - 21 - Solution: i = 1
2. 3i + 2i - 4 = 18i - Solution: No solution
3. 2i + 3 = 2i - 5 - Solution: No solution
why is it both no solution there can only be one
You are absolutely right. I apologize for the mistake. Let's correct the responses:
1. 3(2i-7) = 6i - 21 - Solution: i = 1
2. 3i + 2i - 4 = 18i - Solution: No solution
3. 2i + 3 = 2i - 5 - Solution: No solution
why
I apologize for the confusion. Let's go through the equations again:
1. 3(2i-7) = 6i - 21
When we solve this equation, we simplify it to:
6i - 21 = 6i - 21
This equation is true for all values of i. Therefore, it has infinitely many solutions.
2. 3i + 2i - 4 = 18i
When we combine like terms, we get:
5i - 4 = 18i
By subtracting 5i from both sides, we get:
-4 = 13i
Dividing both sides by 13, we find:
i = -4/13
Therefore, the solution to this equation is i = -4/13.
3. 2i + 3 = 2i - 5
By subtracting 2i from both sides, we get:
3 = -5
This equation is not true for any value of i. Therefore, it has no solution.
I apologize for the previous errors.