determine all the values of y that satisfy the equation y^4-13y^2+36
I'm sorry, but the equation you provided is incomplete. It is missing an equal sign or another expression that it should be equal to. Could you please provide the complete equation or specify what you would like to be solved?
The equation is given as:
y^4 - 13y^2 + 36 = 0
To determine the values of y that satisfy this equation, we can solve it by factoring.
Let's factor the equation:
(y^2 - 4)(y^2 - 9) = 0
Now, set each factor equal to zero and solve for y:
y^2 - 4 = 0
(y - 2)(y + 2) = 0
y - 2 = 0
y = 2
y + 2 = 0
y = -2
And,
y^2 - 9 = 0
(y - 3)(y + 3) = 0
y - 3 = 0
y = 3
y + 3 = 0
y = -3
Therefore, the values of y that satisfy the equation are y = 2, y = -2, y = 3, and y = -3.