Jill solves the equation 3(x−5)+2x=0
. Fill in the blanks with the correct values:(3 points)
3x+ _______+2x=0
5x=________
x= ________
3x-15+2x=0
5x=15
x=3
Solve the equation by filling in the steps: 2(x−3)+21=−3
(4 points)
Step 1: Distribute to get
Step 2: Combine like terms to get
Step 3: Use
to get 2x=−18
Step 4: Use
to get x=−9
Step 1: Distribute to get 2x - 6 + 21 = -3
Step 2: Combine like terms to get 2x + 15 = -3
Step 3: Use subtraction to isolate the variable. Subtract 15 from both sides: 2x = -18
Step 4: Use division to solve for x. Divide both sides by 2: x = -9
Look at the steps for solving the equation and choose a true statement.
3x−9x+1=2(−3x+1)−1
−6x+1=−6x+2−1
−6x+1=−6x+1
(1 point)
Responses
The only solution to the equation is 1.
The only solution to the equation is 1.
There are infinitely many solutions to the equation.
There are infinitely many solutions to the equation.
There is no way to know if there is a solution to the equation.
There is no way to know if there is a solution to the equation.
There is no solution to the equation.
There is no solution to the equation.
The only solution to the equation is -6.
The only solution to the equation is -6.
After combining like terms to simplify the equation 3−15x+24+16x=4x−24−4x
, what would be the next best step to finish solving?(1 point)
Responses
Add 24 to both sides of the equation.
Add 24 to both sides of the equation.
Divide both sides of the equation by 15.
Divide both sides of the equation by 15.
Subtract 24 from both sides of the equation.
Subtract 24 from both sides of the equation.
Add x to both sides of the equation.
Add x to both sides of the equation.
Subtract x from both sides of the equation.
Subtract x from both sides of the equation.
Subtract 27 from both sides of the equation.
Subtract 24 from both sides of the equation.
A student solved the following equation using the following steps:
4(2−3x)=x−2(2x+1)
8−3x=x−4x−2
8−3x=−3x−2
No solution
(2 points)
Based on the student's work, the equation was solved
.
The equation solved correctly would show that it has
solution(s).
Based on the student's work, the equation was solved incorrectly.
The equation solved correctly would show that it has infinitely many solutions.
Select the equation that has infinitely many solutions.(1 point)
Responses
4x+1=4(x+1)
4 x plus 1 is equal to 4 times open paren x plus 1 close paren
3x+5=3x−5
3 x plus 5 is equal to 3 x minus 5
3−3x=−3(x−1)
3 minus 3 x is equal to negative 3 times open paren x minus 1 close paren
3x=2x+1