Consider the graph of p(x). Given that (x−3) is a factor of p(x), is the multiplicity of (x−3) even or odd? Why?
(1 point)
The multiplicity of (x−3) is even because the associated zero, x=3, is odd.
The multiplicity of (x−3) is even because the graph of p(x) touches the x-axis at (3,0) and then turns around.
The multiplicity of (x−3) is odd because the graph of p(x) touches the x-axis at (3,0) and then turns around.
The multiplicity of (x−3) is odd because the associated zero, x=3, is odd.
The correct answer is:
The multiplicity of (x−3) is odd because the graph of p(x) touches the x-axis at (3,0) and then turns around.