Which equation has the same solution for x as x−12=40

?(1 point)
Responses

12−x=40
12 minus x is equal to 40

x4=13
x over 4 is equal to 13

x2=14
x over 2 is equal to 14

x+12=−40

x+12=−40

The length of a rectangle is four meters less than twice its width.

If the area of the rectangle is 96 square meters, what is the length and the width?

(3 points)
Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse.
An expression for the length of the rectangle in terms of the width would be Response area

The formula for the area of a rectangle is Response area

Using trial and error, if the area is 96m^2, then the length and width are Response area

The option "\(area=\frac{1}{2}\left(l\times w\right)\)" (4 of 10) has been selected. Press tab to choose a response area, and spacebar to insert it. Press escape to cancel.

An expression for the length of the rectangle in terms of the width would be \(2w-4\).

The formula for the area of a rectangle is \(A = l \times w\).

Using trial and error, if the area is 96m^2, then the length and width are 12m and 8m, respectively.

The length of a rectangle is four meters less than twice its width.

If the area of the rectangle is 96 square meters, what is the length and the width?

(3 points)

An expression for the length of the rectangle in terms of the width would be

The formula for the area of a rectangle is

Using trial and error, if the area is 96m^2, then the length and width are

WORD BANK: l= 4 -2w
l = 12 & w = 8
l = 24 & w = 4
area = 1/2 (l x w)
w - 2l - 4
l = 8 & w = 12
area = l x w
ll = 2w - 4
l = 4 & w = 24
area = 2l + 2w

An expression for the length of the rectangle in terms of the width would be \(l = 2w - 4\).

The formula for the area of a rectangle is \(A = l \times w\).

Using trial and error, if the area is 96m^2, then the length and width are \(l = 8\) and \(w = 12\).

MATCH THE EQUATION WITH ITS SOLUTION

3i + 2i - 7 = 18 ---->
3 (2i - 7) = 15 --->
3i + 5 = 2i - 7 --->
3i + 5 = 3i + 7 --->
3 (2i + 7) = 6i + 21 --->

WORD BANK: No solution, Infinite solutions, i = -12, i = 5, i = 6, i = 7, i = 11, i = 2

The matching equation and solution pairs are:

3i + 2i - 7 = 18 ---> i = 5

3 (2i - 7) = 15 ---> i = 6

3i + 5 = 2i - 7 ---> No solution

3i + 5 = 3i + 7 ---> No solution

3 (2i + 7) = 6i + 21 ---> Infinite solutions

only one word for each question

Certainly! Here are the matching equation and solution pairs with only one word for each:

3i + 2i - 7 = 18 ----> i = -12 (Solution: -12)
3 (2i - 7) = 15 ---> i = 5 (Solution: 5)
3i + 5 = 2i - 7 ---> No solution (Solution: None)
3i + 5 = 3i + 7 ---> No solution (Solution: None)
3 (2i + 7) = 6i + 21 ---> Infinite solutions (Solution: Infinite)

THE WORD BANK IS ONLY ONE EACH>