A motor produced 10kj of energy each second as mechanical work and lost 5kj as heat to the surrounding calculate the change in internal energy of the motor each second.
To calculate the change in internal energy of the motor each second, we can use the first law of thermodynamics, which states that the change in internal energy (ΔU) of a system is equal to the heat transfer (Q) into the system minus the work done (W) by the system: ΔU = Q - W.
In this case, the motor produces 10 kJ of energy each second as mechanical work (W = 10 kJ) and loses 5 kJ as heat to the surroundings (Q = -5 kJ, since it is lost from the system).
Plugging these values into the equation:
ΔU = Q - W
ΔU = -5 kJ - 10 kJ
ΔU = -15 kJ
Therefore, the change in internal energy of the motor each second is -15 kJ.
To calculate the change in internal energy of the motor each second, we can use the first law of thermodynamics, which states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system.
In this case, the motor produces 10 kJ of energy as mechanical work and loses 5 kJ as heat to the surroundings. The change in internal energy (ΔU) per second can be calculated as follows:
ΔU = Q - W
where Q is the heat added to the system and W is the work done by the system.
Given that the motor produces 10 kJ of mechanical work and loses 5 kJ as heat, we plug these values into the formula:
ΔU = 10 kJ - 5 kJ
ΔU = 5 kJ
Therefore, the change in internal energy of the motor each second is 5 kJ.