A man of 85kg is in an elevator which is accelerating upwards at the rate of 0•8m/s what is the man's apparent weight? (g=9•8m/s^2)
To find the man's apparent weight, we need to consider the force acting on him in the elevator. The force acting on an object can be calculated using the equation:
Force = mass × acceleration
Given:
Mass of the man (m) = 85 kg
Acceleration of the elevator (a) = 0.8 m/s^2
Acceleration due to gravity (g) = 9.8 m/s^2
The force acting on the man (F) can be calculated by using the equation:
F = m × (g + a)
F = 85 kg × (9.8 m/s^2 + 0.8 m/s^2)
F = 85 kg × (10.6 m/s^2)
F = 901 kg·m/s^2
Thus, the man's apparent weight is approximately 901 kg·m/s^2.
To find the man's apparent weight, we need to consider the acceleration and the gravitational force.
First, let's find the gravitational force acting on the man:
Weight = mass × gravity
Weight = 85 kg × 9.8 m/s²
Weight = 833 N
Next, let's find the net force acting on the man:
Net force = mass × acceleration
Net force = 85 kg × 0.8 m/s²
Net force = 68 N
Since the elevator is accelerating upwards, the net force acting on the man is the difference between the gravitational force and the net force:
Apparent weight = Weight - Net force
Apparent weight = 833 N - 68 N
Apparent weight = 765 N
Therefore, the man's apparent weight in the elevator is 765 Newtons.