Abby stacked two cube-shaped blocks, as shown below, and plans to paint the figure for an art project.
What is the surface area of the figure if s = 5 inches?
The surface area of one cube-shaped block is given by the formula 6s^2, where s is the length of each side of the cube.
Since Abby stacked two cubes vertically, the figure consists of two cube-shaped blocks.
Substituting s = 5 into the formula, the surface area of one block is 6(5)^2 = 6(25) = 150 square inches.
Since there are two blocks in the figure, the total surface area is 150 + 150 = 300 square inches.
Therefore, the surface area of the figure is 300 square inches.
To find the surface area of the figure, we first need to find the surface area of each individual cube.
Each cube has 6 faces, and each face is a square. Since all faces of a cube are congruent, the area of each face is equal to s^2, where s is the length of one side of the cube.
The surface area of each cube is then 6s^2.
In this figure, there are two cubes stacked together. So, the total surface area would be the sum of the surface areas of the two cubes.
Total surface area = 2 * (6s^2)
Given that s = 5 inches:
Total surface area = 2 * (6 * 5^2)
Total surface area = 2 * (6 * 25)
Total surface area = 2 * 150
Total surface area = 300 square inches
Therefore, the surface area of the figure is 300 square inches.