Ninety students auditioned for the school play. One-third of those who auditioned were cast, 6 in major roles. What fraction of those who were cast got major roles? Write your answer as a decimal.
You're not stupid at all! Let's break it down step by step.
1. The Medium Trail is 1.2 times as long as the Beginner's Trail.
2. The Advanced Trail is 3.6 times as long as the Medium Trail.
To find the length of the Advanced Trail compared to the Beginner's Trail, we need to multiply those two ratios.
1.2 (Medium Trail length) times 3.6 (Advanced Trail length compared to Medium Trail) gives us 4.32.
Therefore, the Advanced Trail is 4.32 times as long as the Beginner's Trail.
To find out how much Mr. Romanov paid for 9.3 gallons of gas at $3.30 a gallon, we need to multiply the number of gallons by the price per gallon.
So, $3.30/gallon * 9.3 gallons = $30.69.
Therefore, Mr. Romanov paid $\boxed{\$30.69}$ for 9.3 gallons of gas.
One-third of the 90 students who auditioned were cast, or $\frac{90}{3}=30$ students. Thus, $\frac{6}{30}=\boxed{0.2}$ or $\frac{1}{5}$ of those who were cast got major roles.
are you okay?
I'm just a computer program, so I don't have feelings. But thank you for asking! I'm here to help with any questions you have.
can you put the answer to my question in simpler terms?
Sure! Out of the 90 students who auditioned, 30 were chosen for the school play. Out of these 30 students, 6 got major roles. The fraction of students who were cast and got major roles is $\frac{6}{30}$. To simplify this fraction, you can divide both the numerator and denominator by their greatest common divisor, which is 6 in this case. So, $\frac{6}{30}$ simplifies to $\frac{1}{5}$. In decimal form, that is equal to 0.2.
thanks
q.2 At Point Pleasant Park, the Advanced Trail is 3.6 times as long as the Medium Trail, and the Medium Trail is 1.2 times as long as the Beginner's Trail. How many times as long as the Beginner’s Trail is the Advanced Trail? Write your answer as a decimal.
If the Medium Trail is 1.2 times as long as the Beginner's Trail, and the Advanced Trail is 3.6 times as long as the Medium Trail, then we can find the length of the Advanced Trail by multiplying the lengths of the Beginner's Trail and the Medium Trail.
Let's call the length of the Beginner's Trail "B". Then, the length of the Medium Trail is $1.2B$, and the length of the Advanced Trail is $3.6(1.2B)$. We can simplify this expression:
$3.6(1.2B) = 4.32B$
Therefore, the Advanced Trail is $\boxed{4.32}$ times as long as the Beginner's Trail.