The volume of milk in a pitcher is proportional to the depth of the milk. When there are 200 mL of milk in the pitcher, the depth is 8.4 cm. To the nearest milliliter, how much milk is in the pitcher when the depth is 19 cm?
A 452 mL
B 652 mL
C 358 mL
D 88 mL
Let's set up a proportion to solve this problem.
Let V be the volume of milk in mL and D be the depth of the milk in cm.
We know that V is proportional to D, so we can write the equation V = kD, where k is the constant of proportionality.
We also know that when there are 200 mL of milk in the pitcher, the depth is 8.4 cm. So we can substitute these values into the equation to find k:
200 = k * 8.4
Dividing both sides by 8.4, we get:
k = 200 / 8.4 = 23.81
Now we can use this value of k to find the volume of milk when the depth is 19 cm:
V = 23.81 * 19 = 452.39 mL
Rounding to the nearest milliliter, we get:
452 mL
Therefore, the answer is A) 452 mL.
To solve this problem, we can set up a proportion using the given information.
Let's denote the volume of milk in the pitcher as V (in milliliters) and the depth of the milk as D (in centimeters).
We are given that when there are 200 mL of milk in the pitcher, the depth is 8.4 cm. We can write this as a proportion:
200 mL / 8.4 cm = V mL / 19 cm
To find V (the volume of milk when the depth is 19 cm), we can cross-multiply and solve for V:
8.4 cm * V mL = 200 mL * 19 cm
8.4V = 3800
Divide both sides of the equation by 8.4 to isolate V:
V = 3800 / 8.4 ≈ 452.38
Rounding to the nearest milliliter, we have:
V ≈ 452 mL
Therefore, the correct answer is option A: 452 mL.