A scientist heat 30 g of calcium carbonate in the chemical reaction shown. What is the total mass of the products?
The chemical reaction for the heating of calcium carbonate (CaCO3) is as follows:
CaCO3 -> CaO + CO2
In this reaction, calcium carbonate decomposes to form calcium oxide (CaO) and carbon dioxide (CO2).
The molar mass of CaCO3 = 40.08 g/mol + 12.01 g/mol + (3*16.00 g/mol) = 100.09 g/mol
To calculate the mass of the products, we need to consider the stoichiometry of the reaction. From the balanced equation, we can see that 1 mole of CaCO3 gives 1 mole of CaO and 1 mole of CO2.
Therefore, the total molar mass of the products is:
Molar mass of CaO = 40.08 g/mol
Molar mass of CO2 = 12.01 g/mol + (2*16.00 g/mol) = 44.01 g/mol
To find the total mass of the products, we multiply the molar masses by the number of moles of the reactant used.
Number of moles of CaCO3 = mass of CaCO3 / molar mass of CaCO3
= 30 g / 100.09 g/mol
= 0.2999 mol (approximately)
Therefore,
Mass of CaO = 0.2999 mol * 40.08 g/mol
= 12.02 g
Mass of CO2 = 0.2999 mol * 44.01 g/mol
= 13.20 g
The total mass of the products is the sum of the masses of CaO and CO2.
Total mass of the products = Mass of CaO + Mass of CO2
= 12.02 g + 13.20 g
= 25.22 g
Therefore, the total mass of the products is approximately 25.22 g.
The chemical reaction for the thermal decomposition of calcium carbonate (CaCO3) is as follows:
CaCO3(s) → CaO(s) + CO2(g)
From this balanced equation, we can see that one mole of calcium carbonate will produce one mole of calcium oxide and one mole of carbon dioxide.
The molar mass of calcium carbonate is calculated as follows:
Ca = 40.08 g/mol
C = 12.01 g/mol
O = 16.00 g/mol
Total molar mass of CaCO3 = (40.08 + 12.01 + (3 * 16.00)) g/mol = 100.09 g/mol
Given that the scientist heated 30 g of calcium carbonate, we can now calculate the number of moles of calcium carbonate used:
Number of moles = Mass / Molar mass = 30 g / 100.09 g/mol ≈ 0.2998 mol
Since the chemical reaction is 1:1 for calcium carbonate to calcium oxide, the number of moles of calcium oxide produced will also be 0.2998 mol.
The molar mass of calcium oxide (CaO) is calculated as follows:
Ca = 40.08 g/mol
O = 16.00 g/mol
Total molar mass of CaO = 40.08 + 16.00 = 56.08 g/mol
The total mass of calcium oxide produced will be:
Mass = Number of moles * Molar mass = 0.2998 mol * 56.08 g/mol ≈ 16.80 g
Similarly, since the chemical reaction is also 1:1 for calcium carbonate to carbon dioxide, the number of moles of carbon dioxide produced will be 0.2998 mol.
The molar mass of carbon dioxide (CO2) is calculated as follows:
C = 12.01 g/mol
O = 16.00 g/mol
Total molar mass of CO2 = (12.01 + (2 * 16.00)) g/mol = 44.01 g/mol
The total mass of carbon dioxide produced will be:
Mass = Number of moles * Molar mass = 0.2998 mol * 44.01 g/mol ≈ 13.20 g
Therefore, the total mass of the products (calcium oxide + carbon dioxide) will be approximately 16.80 g + 13.20 g = 30 g.