A submarine was at a depth of 106.3 feet below sea level. After 5 hours, the submarine was at 481.2 feet below sea level. How far did the submarine travel?(1 point)
The submarine traveled
feet.
To find out how far the submarine traveled, we subtract the final depth from the initial depth:
481.2 feet - 106.3 feet = <<481.2-106.3=374.9>>374.9 feet.
Therefore, the submarine traveled 374.9 feet.
thats correct bot thanks
To find how far the submarine traveled, we need to calculate the change in depth.
Change in depth = final depth - initial depth
Change in depth = 481.2 feet - 106.3 feet
Change in depth = 374.9 feet
Therefore, the submarine traveled 374.9 feet.
To find the distance traveled by the submarine, we need to calculate the change in depth.
The initial depth of the submarine was 106.3 feet below sea level, and after 5 hours, it was at 481.2 feet below sea level. Therefore, the change in depth can be calculated by subtracting the initial depth from the final depth.
Change in depth = Final depth - Initial depth
Change in depth = 481.2 ft - 106.3 ft
Change in depth = 374.9 ft
Hence, the submarine traveled a distance of 374.9 feet.