Toss two dice. How many times in 180 tosses a 5 will appear on both dice?
To find out how many times a 5 will appear on both dice in 180 tosses, we can calculate the probability of getting a 5 on one die and then multiply it by the number of tosses.
The probability of getting a 5 on one die is 1/6, since there is only one possible outcome out of six that results in a 5.
So, the probability of getting a 5 on both dice is (1/6) * (1/6) = 1/36.
Multiplying this probability by the number of tosses, we get (1/36) * 180 = 5.
Therefore, a 5 will appear on both dice 5 times in 180 tosses.
To find the number of times a 5 will appear on both dice in 180 tosses, we need to calculate the probability of getting a 5 on both dice in one toss.
For a fair six-sided die, the probability of getting a 5 is 1/6. Since we are tossing two dice, the probability of getting a 5 on both dice is (1/6) * (1/6) = 1/36.
Therefore, the expected number of times a 5 will appear on both dice in 180 tosses can be found by multiplying the probability by the number of tosses:
Expected number of times = (1/36) * 180 = 5 times.
So, in 180 tosses, we can expect a 5 to appear on both dice approximately 5 times.