Toss two dice. Predict how many times in 180 tosses a 5 will appear on both dice.
When two dice are rolled, the probability of getting a 5 on each of them is 1/6.
The probability of getting a 5 on both dice in a single toss is the product of the individual probabilities, which is (1/6) * (1/6) = 1/36.
Now, out of 180 tosses, the expected number of times a 5 will appear on both dice is found by multiplying the probability of getting a 5 on both dice in a single toss by the number of tosses:
(1/36) * 180 = 5
Therefore, we can predict that a 5 will appear on both dice around 5 times in 180 tosses.
3/8 x 3/8
To calculate the product of two fractions, we simply multiply the numerators together and the denominators together.
So, (3/8) x (3/8) = (3 x 3) / (8 x 8) = 9 / 64.
Therefore, the product of 3/8 and 3/8 is 9/64.
To find the probability of getting a 5 on both dice, we need to determine the total number of possible outcomes and the number of successful outcomes.
Total possible outcomes when tossing two dice = 6 * 6 = 36 (since each die has 6 faces)
Number of successful outcomes (getting a 5 on both dice) = 1 (since there is only one way to get a 5 on both dice)
So, the probability of getting a 5 on both dice in any single toss = successful outcomes / total outcomes = 1 / 36.
To predict how many times a 5 will appear on both dice in 180 tosses, we can multiply the probability by the number of tosses:
Number of times a 5 will appear on both dice = probability * number of tosses = (1 / 36) * 180 = 5.
Therefore, we can predict that a 5 will appear on both dice approximately 5 times in 180 tosses.