1.what name of procedure is used in fetal monitor to check blood
flow in placenta and uterus during prenatal
checkup in relation to doppler effect.
2.in the inclined the velocity ratio given as L/sin 0.derive this formula
b. suppose L=60kg, h=5m, 0=30 degree. find VR,the effort ,if the inclined is 80% efficient and the work done against friction in raising the load through the height of 5m.
1. The procedure used in a fetal monitor to check blood flow in the placenta and uterus during prenatal checkup in relation to the Doppler effect is called Doppler ultrasound.
2. a) To derive the formula for velocity ratio in an inclined plane, we consider a simple system where a load (L) is being raised to a height (h) on an inclined plane with angle (θ) to the horizontal.
In this system, the weight of the load (L) can be resolved into two components: one acting perpendicular to the inclined plane (mg sinθ) and the other acting parallel to the inclined plane (mg cosθ).
The effort required to lift the load can be considered as the force needed to counteract the component acting parallel to the inclined plane (mg cosθ).
Velocity ratio (VR) is defined as the ratio of the distance moved by the effort to the distance moved by the load. In this case, dE represents the distance moved by the effort and dL represents the distance moved by the load.
Using similar triangles, we can relate the height (h) and the distance moved by the effort (dE) and load (dL). The height is related to the distance moved by the effort using the sine of the angle (sinθ).
Therefore, L/sinθ = VR (Velocity ratio).
b) Given that L = 60 kg, h = 5 m, θ = 30 degrees, and efficiency (η) = 80%.
VR = L/sinθ
= 60 kg / sin(30 degrees) [Using given values]
= 60 kg / 0.5 [sin(30 degrees) = 0.5]
= 120 kg
Efficiency (η) = (VR / actual mechanical advantage) * 100
0.8 = (VR / (L / (mg cosθ))) * 100
Solving for VR:
VR = (0.8 * L * mg cosθ) / 100
= (0.8 * 60 kg * 9.8 m/s^2 * cos(30 degrees)) / 100
= 47.04 kg
The effort required would be 47.04 kg since VR represents the effort needed to counteract the component of weight acting parallel to the inclined plane.
The work done against friction in raising the load through the height of 5m can be calculated as follows:
Work = force * distance
= effort * distance moved by effort
= 47.04 kg * 5 m
= 235.2 J
describe how ultra sound is carried out when checking blood flow in fetus and scanning of vein
When checking blood flow in the fetus and scanning veins, ultrasound is commonly used. Ultrasound uses high-frequency sound waves to create images of the inside of the body.
To check the blood flow in the fetus, a Doppler ultrasound is used. This procedure involves placing a handheld device called a transducer on the mother's abdomen over the area where the blood flow is to be assessed. The transducer emits sound waves into the body, which then bounce back and are detected by the transducer. The transducer measures the change in frequency of the sound waves that occur due to the movement of blood cells. This change in frequency is known as the Doppler effect. By analyzing the Doppler shift, the direction and velocity of blood flow in the placenta and uterus can be determined.
During a vein scan, a different type of ultrasound is used. In this case, a gel is applied to the skin over the vein being examined to ensure good contact between the skin and the transducer. The transducer is then pressed against the skin and manipulated to obtain the best angle for imaging the vein. The transducer emits sound waves that pass through the skin and other tissues, bounce back off structures within the body, and are picked up by the transducer. These echoes are converted into images of the vein on a monitor. By visualizing the vein, healthcare professionals can assess its size, shape, and blood flow patterns.
Ultrasound is a non-invasive and safe procedure for checking blood flow in the fetus and scanning veins. It provides real-time imaging and requires no use of ionizing radiation. Ultrasound can provide valuable information for diagnosis and monitoring, allowing doctors to assess the health and well-being of both the fetus and the venous system in a safe and effective manner.
covert 38.9 degree to F
To convert 38.9 degrees Celsius to Fahrenheit, you can use the following formula:
°F = (°C * 9/5) + 32
Plugging in the value for Celsius:
°F = (38.9 * 9/5) + 32
°F = (70.02) + 32
°F = 102.02
Therefore, 38.9 degrees Celsius is approximately 102.02 degrees Fahrenheit.
1. The procedure used in fetal monitoring to check blood flow in the placenta and uterus during prenatal checkup, in relation to the Doppler effect, is called Doppler ultrasound.
2. To derive the formula for the velocity ratio in an inclined plane, we can start with the basic trigonometric relationship between the length of the inclined plane, the height, and the angle of inclination.
a. Let L be the length of the inclined plane, h be the height, and θ be the angle of inclination.
Using trigonometry, we have:
sin θ = h / L
Rearranging the equation, we get:
L = h / sin θ
b. Given:
L = 60 kg
h = 5 m
θ = 30 degrees
To find the velocity ratio, VR, we can substitute the values into the derived formula:
L = h / sin θ
VR = L / sin θ
VR = (5 m) / sin 30°
VR = (5 m) / (0.5)
VR = 10 m
The velocity ratio, VR, is equal to 10 m.
To find the effort, we can use the formula for mechanical advantage in an inclined plane:
Mechanical Advantage (MA) = Force Output / Force Input
MA = VR / Efficiency
Given:
VR = 10 m
Efficiency = 80%
MA = 10 m / 0.8
MA = 12.5
The mechanical advantage is 12.5.
To find the work done against friction in raising the load through the height of 5 m, we can use the formula:
Work = Force x Distance
Given:
Efficiency = 80%
Work = ?
Effort = Input Force
Effort = 60 kg (gravitational force)
Effort = 60 kg x 9.8 m/s^2 (acceleration due to gravity)
Effort = 588 N
Output Force = Effort / MA
Output Force = 588 N / 12.5
Output Force = 47.04 N
Work = Output Force x Distance
Work = 47.04 N x 5 m
Work = 235.2 Joules
The work done against friction in raising the load through the height of 5 m is 235.2 Joules.
1. The procedure used in fetal monitoring to check blood flow in the placenta and uterus in relation to the Doppler effect is called Doppler ultrasound. This involves using ultrasound technology to detect and analyze the movement of blood through the vessels in the placenta and uterus. The Doppler effect is utilized to measure the shift in frequency of sound waves as they bounce off the moving blood cells, enabling the calculation of blood flow velocity.
To perform Doppler ultrasound, a healthcare professional places a transducer device on the mother's abdomen, which emits high-frequency sound waves. These sound waves penetrate the tissues and bounce off the red blood cells in the blood vessels. The returning sound waves are then analyzed to determine the direction and speed of blood flow.
2a. Deriving the formula for velocity ratio in an inclined plane:
In an inclined plane, there are two forces acting on an object - the gravitational force (weight) and the applied force (effort) required to move the object up the inclined plane. The sine of the angle of inclination relates the height of the plane to its length.
Let L be the length of the plane, and h be the height of the plane. The formula for velocity ratio (VR) is given by VR = L/sinθ, where θ is the angle of inclination.
To derive this formula, we can divide L by sinθ:
L/sinθ = (L/h) / (sinθ/h) = (L/h) / (h/L) = (L/h) * (L/h) = (L^2) / (h^2)
Therefore, VR = (L^2) / (h^2)
2b. Given L = 60 kg, h = 5 m, and θ = 30 degrees:
VR = (L^2) / (h^2) = (60^2) / (5^2) = 3600 / 25 = 144
The velocity ratio (VR) is 144.
To calculate the effort, we need to utilize the concept of mechanical advantage. The mechanical advantage (MA) is given by MA = 1 / (1 - (frictional force/effort force)).
Since the inclined plane is stated to be 80% efficient, we can deduce that the frictional force is 20% of the effort force. Therefore, the frictional force is 0.2 times the effort force.
MA = 1 / (1 - 0.2) = 1 / 0.8 = 1.25
We know that MA = VR / effort.
1.25 = 144 / effort
effort = 144 / 1.25 = 115.2 kg
The effort required is 115.2 kg.
To calculate the work done against friction in raising the load through the height of 5m, we can use the formula:
Work done = (force applied) * (distance moved)
Here, the force applied is the effort, which is 115.2 kg, and the distance moved is the height of the inclined plane, which is 5m.
Work done = 115.2 kg * 5m = 576 J (Joules)
Therefore, the work done against friction in raising the load through the height of 5m is 576 Joules.