If you dissolve 2.70 g of NaCl in 425 mL of water, what is the molarity of the solution?
To find the molarity of the solution, we need to first calculate the number of moles of NaCl in 2.70 g.
The molar mass of NaCl is 58.44 g/mol.
Number of moles = mass / molar mass
Number of moles of NaCl = 2.70 g / 58.44 g/mol = 0.0463 mol
Next, we need to calculate the volume of the solution in liters.
Volume of the solution = 425 mL = 425/1000 L = 0.425 L
Molarity = number of moles / volume of solution
Molarity = 0.0463 mol / 0.425 L ≈ 0.109 mol/L
Therefore, the molarity of the NaCl solution is approximately 0.109 mol/L.
To find the molarity of the solution, we need to calculate the number of moles of NaCl and then divide it by the volume of the solution in liters.
Step 1: Convert the mass of NaCl from grams to moles.
To do this, we divide the mass of NaCl by its molar mass.
The molar mass of NaCl is the sum of the atomic masses of sodium (Na) and chlorine (Cl), which is 22.99 g/mol + 35.45 g/mol = 58.44 g/mol.
Number of moles of NaCl = mass of NaCl / molar mass of NaCl
Number of moles of NaCl = 2.70 g / 58.44 g/mol
Number of moles of NaCl = 0.0463 mol
Step 2: Convert the volume of the solution from milliliters to liters.
To do this, we divide the volume by 1000.
Volume of the solution = 425 mL / 1000 mL/L
Volume of the solution = 0.425 L
Step 3: Calculate the molarity.
Molarity (M) = moles of solute / volume of solution (in liters)
Molarity (M) = 0.0463 mol / 0.425 L
Molarity (M) = 0.109 M
Therefore, the molarity of the solution is 0.109 M.