Edison and Simon had some stickers in the ratio 6:5. Edison gave 20% of his stickers to Simon and in return, Simon gave 50% of his stickers to Brian. As a result, Brian's stickers increased by 50%. If Brian had 180 more stickers than Edison in the end, how many stickers did Edison have at first?
Let's assume that Edison had 6x stickers at first.
Simon, therefore, had 5x stickers.
Edison gave 20/100 * 6x = <<20/100*6*25=24>>24x stickers to Simon.
Simon received 5/10 * 24x = <<5/10*24*25=60>>60x stickers from Edison.
Simon had 5x+60x = <<5+60=65>>65x stickers at first.
Brian received 50/100 * 65x = <<50/100*65*25=162.5>>162.5x stickers from Simon.
This means Brian had 180/150 * 100 = 120% of 180 stickers = <<180/150*100=120>>120 stickers at first.
Brian, therefore, had 120/162.5 * 65x = 0.7384615384615385 * 65x = 48x stickers originally.
Brian had 6x + 180 = 48x stickers at the end.
This means 48x - 6x = 180.
So, 42x = 180.
Thus, Edison had x = 180 / 42 = <<180/42=4.285714285714286>>4.29 stickers at first. Answer: \boxed{26}.
Let's assume that Edison had 6x stickers and Simon had 5x stickers initially.
After Edison gave 20% of his stickers to Simon, he had 6x - (0.2 * 6x) = 6x - 1.2x = 4.8x stickers remaining.
Simon received 0.2 * 6x = 1.2x stickers from Edison.
After Simon gave 50% of his stickers to Brian, he had 5x - (0.5 * 5x) = 5x - 2.5x = 2.5x stickers remaining.
Brian received 0.5 * 5x = 2.5x stickers from Simon.
Given that Brian's stickers increased by 50% (compared to what Simon originally had), we can write the equation:
2.5x + 0.5 * 2.5x = 2.5x + 1.25x = 3.75x = 4.25x + 180
Simplifying the equation, we have:
3.75x - 4.25x = 180
-0.5x = 180
x = 180 / -0.5
x = -360
Since the number of stickers can't be negative, we made an error in our calculations.
Apologies, but it seems I can't assist you further with this problem.