Find a rational number with one decimal place that is between 17−−√ and 18−−√ .
bro what
wtf is that bs LOL
To find a rational number between $\sqrt{17}$ and $\sqrt{18}$, we can take the average of the two numbers. The average is \begin{align*}
\frac{(\sqrt{17}) + (\sqrt{18})}{2} &= \frac{(\sqrt{17}) + (\sqrt{18})}{2}\cdot \frac{(\sqrt{17}) - (\sqrt{18})}{(\sqrt{17}) - (\sqrt{18})}\\
&=\frac{17+18}{2(\sqrt{17})+\sqrt{18}}\\
&= \frac{35}{2\sqrt{17}+\sqrt{18}}\cdot\frac{\sqrt{18}-\sqrt{17}}{\sqrt{18}-\sqrt{17}\\
&= \frac{35(\sqrt{18}-\sqrt{17})}{2(\sqrt{17})^2 + 2\sqrt{17}\sqrt{18} + (\sqrt{18})^2-(\sqrt{17})^2}\\
&= \frac{(35)(\sqrt{18}-\sqrt{17})}{(\sqrt{18})^2 -(\sqrt{17})^2}\\
&=\frac{(35)(\sqrt{18}-\sqrt{17})}{18-17}\\
&= (35)(\sqrt{18}-\sqrt{17}).
\end{align*}Since $4^2 = 16$ and $5^2 = 25$, we know $16 < 17 < 18 < 25$, and squaring each of these numbers yields $256 < 289 < 324$. So a number between $\sqrt{17}$ and $\sqrt{18}$ is $(35)(4-5)=\boxed{-35}$.
Better do it yourself! This so Called "Robot" gives very different answers and sometimes random.
that- is a very interesting answer xDDDD
bro really just gave out his program
the answer is 4.2
4.2 is right
To find a rational number with one decimal place that is between √17 and √18, we can start by evaluating the decimal values of √17 and √18.
Using a calculator, we can find that √17 is approximately 4.1231, and √18 is approximately 4.2426.
Since we are looking for a rational number with one decimal place, we need to find a number between 4.1231 and 4.2426 that has only one digit after the decimal point.
One way to do this is to round the numbers to one decimal place. When rounding, if the digit after the decimal point is less than 5, we round down; if it is 5 or greater, we round up.
Rounding 4.1231 to one decimal place gives us 4.1, and rounding 4.2426 gives us 4.2.
Therefore, the rational number with one decimal place that is between √17 and √18 is 4.2.