2. A stone that starts from rest is in free fall for 8.00s. What is the stone's displacement during this time?
The displacement of the stone during free fall can be calculated using the formula:
displacement = (1/2) * acceleration * time^2
The acceleration due to gravity (g) is approximately 9.8 m/s^2.
Given that the stone is in free fall for 8.00s, we can substitute the values into the formula:
displacement = (1/2) * 9.8 * (8.00)^2
displacement = (1/2) * 9.8 * 64
displacement = 313.6 m
Therefore, the stone's displacement during this time is 313.6 meters.
To determine the displacement of the stone during free fall, we can use the equation:
displacement = initial velocity × time + 0.5 × acceleration × time^2
In this case, since the stone starts from rest, the initial velocity is 0 m/s. The acceleration due to gravity is approximately 9.8 m/s^2.
Plugging in the values, we have:
displacement = 0 × 8 + 0.5 × 9.8 × (8)^2
displacement = 0 + 0.5 × 9.8 × 64
displacement = 0 + 0.5 × 627.2
displacement = 313.6 meters
Therefore, the stone's displacement during the 8 seconds of free fall is 313.6 meters.