Jenn kept track of the amount of time she spent on homework for each subject.
A 2-column table with 4 rows. Column 1 is unlabeled with entries Math, Science, Language Arts, Social Studies. Column 2 is labeled Time in hours with entries five-sixths, StartFraction 37 over 60 EndFraction, two-thirds, StartFraction 17 over 30 EndFraction.
Which subject did she spend the least time on?
To determine which subject Jenn spent the least time on, we need to compare the values in column 2.
The values in column 2 represent fractions of hours:
- Five-sixths can be written as 5/6.
- StartFraction 37 over 60 EndFraction is equivalent to the decimal 0.617.
- Two-thirds can be written as 2/3.
- StartFraction 17 over 30 EndFraction is equivalent to the decimal 0.567.
Comparing the fractions and decimals, we can see that:
- 5/6 is greater than 0.617
- 2/3 is less than 0.617
- 2/3 is greater than 0.567
- 5/6 is greater than 0.567
Therefore, the subject Jenn spent the least time on is Language Arts.
To determine which subject Jenn spent the least time on, we can compare the values in the second column of the table. Let's list the times in hours for each subject:
Math: five-sixths
Science: StartFraction 37 over 60 EndFraction
Language Arts: two-thirds
Social Studies: StartFraction 17 over 30 EndFraction
To compare these values, we need to find a common denominator. The least common denominator of 6, 60, 3, and 30 is 60.
Converting the times to a denominator of 60, we get:
Math: StartFraction 55 over 60 EndFraction
Science: StartFraction 37 over 60 EndFraction
Language Arts: StartFraction 40 over 60 EndFraction
Social Studies: StartFraction 34 over 60 EndFraction
Now, we can see that Jenn spent the least time on Science, which is StartFraction 37 over 60 EndFraction in hours.