Let A = (0, 1, 5) ,B = (-sqrt 14,5,1) . Find the angle between A and B.

To find the angle between two vectors, we can use the dot product formula:

A · B = |A| |B| cos(θ)

where A · B is the dot product of vectors A and B, |A| and |B| are the magnitudes of vectors A and B, and θ is the angle between them.

First, let's calculate the magnitudes of vectors A and B:

|A| = √(0^2 + 1^2 + 5^2) = √26
|B| = √((-√14)^2 + 5^2 + 1^2) = √(14 + 26) = √40 = 2√10

Next, let's calculate the dot product of vectors A and B:

A · B = (0*-sqrt14) + (1*5) + (5*1) = -√14 + 5 + 5 = 10 - √14

Now, let's substitute the values into the dot product formula and solve for θ:

10 - √14 = √26 * 2√10 * cos(θ)

Divide both sides by √26 * 2√10:

(10 - √14) / (2√26√10) = cos(θ)

Simplify the expression:

(10 - √14) / (2√(260)) = cos(θ)

Now, use a calculator to evaluate the right-hand side expression:

(10 - √14) / (2√(260)) ≈ 0.205

Next, use the inverse cosine function to find the angle θ:

θ ≈ arccos(0.205) ≈ 1.361 radians or 78.015 degrees

Therefore, the angle between vectors A and B is approximately 1.361 radians or 78.015 degrees.

To find the angle between two vectors A and B, you can use the dot product formula:

A • B = |A| * |B| * cos(theta)

where A • B is the dot product, |A| and |B| are the magnitudes of vector A and vector B respectively, and theta is the angle between the two vectors.

Let's calculate the dot product first:

A • B = (0 * -sqrt(14)) + (1 * 5) + (5 * 1)
= 0 - sqrt(14) + 5
= 5 - sqrt(14)

Next, let's calculate the magnitudes of A and B:

|A| = sqrt(0^2 + 1^2 + 5^2)
= sqrt(0 + 1 + 25)
= sqrt(26)

|B| = sqrt((-sqrt(14))^2 + 5^2 + 1^2)
= sqrt(14 + 25 + 1)
= sqrt(40)

Now, substitute the dot product and magnitudes into the original formula:

5 - sqrt(14) = sqrt(26) * sqrt(40) * cos(theta)

To solve for the angle theta, rearrange the equation:

cos(theta) = (5 - sqrt(14)) / (sqrt(26) * sqrt(40))

Now, calculate the value of cos(theta):

cos(theta) ≈ 0.0937

Finally, find the angle theta by taking the inverse cosine (cos^-1) of cos(theta):

theta ≈ cos^-1(0.0937)

Using a calculator, the approximate value of theta is:

theta ≈ 84.83 degrees.

Therefore, the angle between vectors A and B is approximately 84.83 degrees.