Given:
a=5.50m/s^2
t=20.25s
Vi=0m/s
find:d=?
d=Vi+1/2 at^2
To find the distance (d), we can use the equation d = Vi + 1/2 at^2.
Given that Vi (initial velocity) is 0 m/s, a (acceleration) is 5.50 m/s^2, and t (time) is 20.25 s, we can substitute these values into the equation:
d = 0 + 1/2 (5.50) (20.25)^2
Simplifying further:
d = 0 + 1/2 (5.50) (410.0625)
d = 0 + 1/2 (2255.34375)
d = 0 + 1127.671875
Therefore, d ≈ 1127.67 meters.
To find the value of "d" using the given information, we can substitute the given values into the formula:
d = Vi + 1/2 at^2
Given:
a = 5.50 m/s^2 (acceleration)
t = 20.25 s (time)
Vi = 0 m/s (initial velocity)
Substituting these values into the formula:
d = 0 + 1/2 * 5.50 * (20.25)^2
First, we will evaluate (20.25)^2:
d ≈ 0 + 1/2 * 5.50 * 410.0625
Next, we multiply 1/2 and 5.50:
d ≈ 0 + 2.75 * 410.0625
Now, we perform the multiplication:
d ≈ 1127.7171875
Therefore, the value of "d" is approximately 1127.72 meters.