Q2. Consider the following code and the variables declared in the memory: [8+2 = 10 POINTS]

ORG 0x0400
Address:
0400H MOV BX, ARRAY
MOV CX, [BX]
MOV AX, [BX+2]
MOV DX, [BX+4]
PUSH CX
CALL SHERIDAN
MOV [BX], CX
MOV [BX+2], AX
MOV [BX+4], DX
ADD AX, DX
MOV [BX+6], AX
SHL AX, 1
MOV [BX+8], AX
0430H INT3
ARRAY DW 03H, 09H, 56H, 67H, 09H
SHERIDAN:
POP CX
AGAIN:
DEC AX
INC DX
LOOP AGAIN
RET
a. After executing the above code what would be the content of ARRAY variable. You must determine values for all the elements (five elements) in the ARRAY. You must show your work.
b. As above, the address allocated for INT3 is 0430H. As such, what are the addresses (the range) allocated for the ARRAY variable?

a. After executing the code, the content of the ARRAY variable would be:

ARRAY = [03H, 09H, 56H, 67H, 09H]

To determine the values for all the elements in the ARRAY, we can follow the code step by step:

1. MOV BX, ARRAY - BX = 0406H (address of the first element in the ARRAY)

2. MOV CX, [BX] - CX = 03H (value of the first element in the ARRAY)

3. MOV AX, [BX+2] - AX = 09H (value of the second element in the ARRAY)

4. MOV DX, [BX+4] - DX = 56H (value of the third element in the ARRAY)

5. PUSH CX - Pushes the value of CX (03H) onto the stack

6. CALL SHERIDAN - Calls the subroutine SHERIDAN

Inside SHERIDAN:
POP CX - Pops the value of CX (03H) from the stack

AGAIN:
DEC AX - Decrements the value of AX (09H)
INC DX - Increments the value of DX (57H)
LOOP AGAIN - Loops back to AGAIN if CX (03H) is not zero

After the loop, AX and DX will have the values AX = 07H and DX = 59H

RET - Returns from the subroutine

7. MOV [BX], CX - Stores the value of CX (03H) in the first element of the ARRAY

8. MOV [BX+2], AX - Stores the value of AX (07H) in the second element of the ARRAY

9. MOV [BX+4], DX - Stores the value of DX (59H) in the third element of the ARRAY

10. ADD AX, DX - AX = AX + DX = 07H + 59H = 60H

11. MOV [BX+6], AX - Stores the value of AX (60H) in the fourth element of the ARRAY

12. SHL AX, 1 - Shifts the bits of AX to the left by 1 position, AX = 00C0H

13. MOV [BX+8], AX - Stores the value of AX (00C0H) in the fifth element of the ARRAY

Therefore, the final content of the ARRAY variable would be:

ARRAY = [03H, 07H, 59H, 60H, 00C0H]

b. The addresses allocated for the ARRAY variable would range from 0406H to 040AH.

Can you explain b)?

Sure!

In the given code, the address of the first element of the ARRAY variable is assigned to the BX register using the instruction `MOV BX, ARRAY`. So, BX will contain the address 0406H, which points to the first element of the ARRAY.

The size of each element in the ARRAY is 2 bytes because each element is defined as DW (word) in the code. Therefore, to determine the range of addresses allocated for the ARRAY variable, we need to consider the size of each element.

The BX register holds the base address of the ARRAY. Adding an offset of 0 accesses the first element, an offset of 2 accesses the second element, an offset of 4 accesses the third element, and so on.

Since each element is 2 bytes, the address range allocated for the ARRAY variable is:
- Starting address: BX + 0 = 0406H + 0 = 0406H
- Ending address: BX + (number of elements - 1) * size of each element = 0406H + (5 - 1) * 2 = 040AH

Therefore, the addresses allocated for the ARRAY variable range from 0406H to 040AH.

a. To determine the content of the ARRAY after executing the code, we need to analyze the code step-by-step.

1. MOV BX, ARRAY
This line moves the memory address of the ARRAY variable into the BX register.

2. MOV CX, [BX]
This line moves the value at the memory address stored in BX (which is the first element of the ARRAY) into the CX register. So, CX = 03H.

3. MOV AX, [BX+2]
This line moves the value at the memory address BX+2 (which is the third element of the ARRAY) into the AX register. So, AX = 56H.

4. MOV DX, [BX+4]
This line moves the value at the memory address BX+4 (which is the fifth element of the ARRAY) into the DX register. So, DX = 09H.

5. PUSH CX
This line pushes the value of CX onto the stack.

6. CALL SHERIDAN
This line calls the subroutine SHERIDAN.

SHERIDAN:
a. POP CX
This line pops the value from the top of the stack and stores it in CX. So, CX = 03H.
b. AGAIN:
c. DEC AX
This line decrements the value in AX by 1. So, AX = 55H.
d. INC DX
This line increments the value in DX by 1. So, DX = 0AH.
e. LOOP AGAIN
This line decrements the value in the CX register by 1 and jumps to the label AGAIN if CX is not zero. In this case, CX is 03H, so it decrements to 02H and jumps back to label AGAIN.
f. DEC AX
This line decrements the value in AX by 1. So, AX = 54H.
g. INC DX
This line increments the value in DX by 1. So, DX = 0BH.
h. LOOP AGAIN
This line decrements the value in the CX register by 1 and jumps to the label AGAIN if CX is not zero. In this case, CX is 02H, so it decrements to 01H and jumps back to label AGAIN.
i. DEC AX
This line decrements the value in AX by 1. So, AX = 53H.
j. INC DX
This line increments the value in DX by 1. So, DX = 0CH.
k. LOOP AGAIN
This line decrements the value in the CX register by 1 and jumps to the label AGAIN if CX is not zero. In this case, CX is 01H, so it decrements to 00H and exits the loop.
l. RET
This line returns from the subroutine.

7. MOV [BX], CX
This line moves the value in CX (which is 03H) back into the first element of the ARRAY.

8. MOV [BX+2], AX
This line moves the value in AX (which is 53H) to the third element of the ARRAY.

9. MOV [BX+4], DX
This line moves the value in DX (which is 0CH) to the fifth element of the ARRAY.

10. ADD AX, DX
This line adds the values of AX (53H) and DX (0CH) and stores the result in AX. So, AX = 5FH.

11. MOV [BX+6], AX
This line moves the value in AX (which is 5FH) to the seventh element of the ARRAY.

12. SHL AX, 1
This line shifts the bits of AX one position to the left. So, AX = BEH.

13. MOV [BX+8], AX
This line moves the value in AX (which is BEH) to the ninth element of the ARRAY.

If we summarize the above steps, the content of the ARRAY after executing the code would be:
ARRAY = [03H, 09H, 53H, 67H, 0CH, 09H, 5FH, BEH, 0CH]

b. The address allocated for INT3 is 0430H. As such, the range allocated for the ARRAY variable is from 0400H to 040A, i.e., 0400H, 0402H, 0404H, 0406H, 0408H, and 040AH.