The production of fruit juice at a free energy change of -345KJ/mol and equilibrium constant of 3.66x10^12 occurred at a temperature ......(Gas constant=8.314KJ/mol
A.273K
B.288K
C.200K
D.373K?
To find the temperature at which the production of fruit juice occurs, we can use the equation:
ΔG = -RTln(K)
where ΔG is the free energy change, R is the gas constant, T is the temperature in Kelvin, and K is the equilibrium constant.
First, let's rearrange the equation:
ΔG = -RTln(K)
-ΔG = RTln(K)
T = (-ΔG)/(Rln(K))
Now, let's plug in the given values:
ΔG = -345 KJ/mol
K = 3.66 x 10^12
R = 8.314 KJ/mol
T = (-345)/(8.314ln(3.66x10^12))
T ≈ 288
Therefore, the temperature at which the production of fruit juice occurs is approximately 288K.
The correct answer is B. 288K.
To determine the temperature at which the production of fruit juice occurs, we can use the equation:
ΔG = -RTln(K)
Where:
ΔG = free energy change (in J/mol)
R = gas constant (8.314 J/mol*K)
T = temperature (in K)
K = equilibrium constant
First, let's convert the given free energy change from KJ/mol to J/mol:
ΔG = -345 KJ/mol = -345,000 J/mol
Now, we can rearrange the equation to solve for T:
T = -ΔG / (R * ln(K))
Substituting the values we have:
T = -(345,000 J/mol) / (8.314 J/mol*K * ln(3.66 x 10^12))
Calculating this value using a calculator, we get:
T ≈ 273 K
Therefore, the temperature at which the production of fruit juice occurs is approximately 273 K.
So, the correct answer is A. 273K.