The length of a table is 4m longer than the width. The are is 60m^2. Find the dimensions of the table.
Let's assume that the width of the table is 'x' meters.
According to the given information, the length of the table is 4 meters longer than the width, so it would be 'x + 4' meters.
The area of the table is given by the product of length and width, which is '60m²'.
So, we have the equation:
Length * Width = Area
(x + 4) * x = 60
Expanding the equation:
x² + 4x = 60
Rearranging the equation:
x² + 4x - 60 = 0
Now we can solve this quadratic equation by factoring or using the quadratic formula.
Factoring, we get:
(x - 6)(x + 10) = 0
Setting each factor equal to zero:
x - 6 = 0 or x + 10 = 0
Solving each equation, we find:
x = 6 or x = -10
Since the width cannot be negative, we discard the solution 'x = -10'.
Therefore, the width of the table is 'x = 6' meters.
And the length of the table would be 'x + 4 = 6 + 4 = 10' meters.
So, the dimensions of the table are:
Width = 6 meters
Length = 10 meters
Let's assume the width of the table is x meters.
According to the given information, the length of the table is 4 meters longer than the width. Therefore, the length is x + 4 meters.
The formula to calculate the area of a rectangle is length × width.
In this case, the area is given as 60 m². So we can set up the following equation:
(x + 4) × x = 60
Expanding the equation, we get:
x² + 4x = 60
Rearranging the equation, we get:
x² + 4x - 60 = 0
Now, let's solve this quadratic equation for the value of x. This equation can be factored as:
(x - 6)(x + 10) = 0
Setting each factor equal to zero, we get:
x - 6 = 0 or x + 10 = 0
Solving each equation gives us:
x = 6 or x = -10
Since the width of the table cannot be negative, we can disregard the negative value.
Therefore, the width of the table is 6 meters.
And the length of the table is 6 + 4 = 10 meters.
So, the dimensions of the table are:
Width = 6 meters
Length = 10 meters