A 25ml solution of 0.5 M NaOH is titrated until neutralised into a 50mL sample of HNO3.what was the concentration of the HNO3?
To find the concentration of HNO3, we can use the equation:
M1V1 = M2V2
Where:
M1 = concentration of NaOH solution
V1 = volume of NaOH solution
M2 = concentration of HNO3
V2 = volume of HNO3 solution
Given:
M1 = 0.5 M
V1 = 25 mL = 0.025 L
V2 = 50 mL = 0.05 L
Plugging the given values into the equation:
0.5 M x 0.025 L = M2 x 0.05 L
0.0125 = M2 x 0.05
M2 = 0.0125 / 0.05
M2 = 0.25 M
Therefore, the concentration of HNO3 is 0.25 M.
To determine the concentration of HNO3, we can use the equation:
M1V1 = M2V2
Where:
M1 = initial concentration of NaOH (0.5 M)
V1 = volume of NaOH solution (25 mL)
M2 = final concentration of HNO3 (what we need to find)
V2 = volume of HNO3 solution (50 mL)
Substituting the given values, we have:
(0.5 M)(25 mL) = M2(50 mL)
Now, let's solve for M2:
M2 = (0.5 M)(25 mL) / (50 mL)
M2 = 12.5 / 50
M2 = 0.25 M
Therefore, the concentration of HNO3 is 0.25 M.