III O CHEMICAL REACTIONS Writing net ionic equations The following chemical reaction takes place in aqueous solution: SnCl(aq)+(NH4), S(aq) SnS(s)+2 NH,Cl(aq) Write the net ionic equation for this rea
Melodysweetpop5540
The net ionic equation for this reaction can be written as:
Sn2+(aq) + S2-(aq) → SnS(s)
To write the net ionic equation for the given reaction, we need to identify the spectator ions. Spectator ions are ions that do not participate in the chemical reaction and remain unchanged throughout the reaction.
Breaking down the given ionic equation:
SnCl(aq) + (NH4)2S(aq) → SnS(s) + 2 NH4Cl(aq)
First, we need to write the balanced molecular equation:
SnCl2(aq) + (NH4)2S(aq) → SnS(s) + 2 NH4Cl(aq)
Next, we need to separate the reactants and products into their respective ions:
SnCl2(aq) → Sn2+(aq) + 2 Cl-(aq)
(NH4)2S(aq) → 2 NH4+(aq) + S2-(aq)
SnS(s) → Sn2+(aq) + S2-(aq)
2 NH4Cl(aq) → 2 NH4+(aq) + 2 Cl-(aq)
Now, let's remove the spectator ions (ions that appear on both sides of the equation):
The spectator ions in this reaction are the Cl- ions (which appear on both sides of the equation) and the NH4+ ions (which also appear on both sides of the equation).
The net ionic equation for this reaction is:
Sn2+(aq) + S2-(aq) → SnS(s)
So, the net ionic equation for the given reaction is Sn2+(aq) + S2-(aq) → SnS(s).