ow much heat is needed to raise 50. g of aluminum from 20.0 °C to 100. °C? (Al sp. heat=0.215 cal/g°C)
To calculate the heat needed to raise the temperature of a substance, we can use the formula:
q = m * c * ΔT
Where:
- q is the heat needed (in calories)
- m is the mass of the substance (in grams)
- c is the specific heat capacity of the substance (in cal/g°C)
- ΔT is the change in temperature (in °C)
Given:
- m = 50. g
- c = 0.215 cal/g°C
- ΔT = 100. °C - 20. °C = 80. °C
We can plug in these values into the formula to find the heat needed:
q = 50. g * 0.215 cal/g°C * 80. °C
q = 860. cal
Therefore, 860 calories of heat are needed to raise 50. g of aluminum from 20.0 °C to 100. °C.
To find out how much heat is needed to raise the temperature of 50.0 g of aluminum from 20.0 °C to 100. °C, you can use the formula:
Q = m * C * ΔT
Where:
Q = heat (in calories)
m = mass of aluminum (in grams)
C = specific heat capacity of aluminum (in cal/g°C)
ΔT = change in temperature (in °C)
Plugging in the values given:
m = 50.0 g
C = 0.215 cal/g°C
ΔT = 100.0 °C - 20.0 °C = 80.0 °C
Now, substitute these values into the formula:
Q = 50.0 g * 0.215 cal/g°C * 80.0 °C
Simplifying the expression:
Q = 860.0 cal * 80.0 °C
Q = 68,800 cal
Therefore, 68,800 calories of heat is needed to raise 50.0 g of aluminum from 20.0 °C to 100. °C.